通过测试访问数据库，会play.exceptions.JPAException：JPA的情况下未初始化

Question

我试图通过使用PlayFremwork一个类来访问数据库，并编写测试

 
import static org.junit.Assert.*; 
import javax.persistence.EntityManager; 
import models.com.vlist.entity.classes.Playlist; 
import org.junit.Test; 
import play.db.jpa.JPA; 
import play.db.jpa.Transactional; 
import play.jobs.OnApplicationStart; 
import play.mvc.Scope.Session; 
public class PlaylistTest { 
@Test 
    @Transactional 
    public void insertIntoPlaylist() { 
     Playlist playlist = new Playlist(); 
     playlist.setId(1); 
     playlist.setName("test"); 

     EntityManager em = JPA.em(); 
     em.persist(playlist); 
    } 
} 

错误堆栈跟踪是：

 

    play.exceptions.JPAException: The JPA context is not initialized. JPA Entity Manager automatically start when one or more classes annotated with the @javax.persistence.Entity annotation are found in the application. 
     at play.db.jpa.JPA.get(JPA.java:22) 
     at play.db.jpa.JPA.em(JPA.java:51) 
     at PlaylistTest.insertIntoPlaylist(PlaylistTest.java:23) 
     at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) 
     at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39) 
     at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25) 
     at java.lang.reflect.Method.invoke(Method.java:597) 
     at org.junit.runners.model.FrameworkMethod$1.runReflectiveCall(FrameworkMethod.java:44) 
     at org.junit.internal.runners.model.ReflectiveCallable.run(ReflectiveCallable.java:15) 
     at org.junit.runners.model.FrameworkMethod.invokeExplosively(FrameworkMethod.java:41) 
     at org.junit.internal.runners.statements.InvokeMethod.evaluate(InvokeMethod.java:20) 
     at org.junit.runners.BlockJUnit4ClassRunner.runChild(BlockJUnit4ClassRunner.java:76) 
     at org.junit.runners.BlockJUnit4ClassRunner.runChild(BlockJUnit4ClassRunner.java:50) 
     at org.junit.runners.ParentRunner$3.run(ParentRunner.java:193) 
     at org.junit.runners.ParentRunner$1.schedule(ParentRunner.java:52) 
     at org.junit.runners.ParentRunner.runChildren(ParentRunner.java:191) 
     at org.junit.runners.ParentRunner.access$000(ParentRunner.java:42) 
     at org.junit.runners.ParentRunner$2.evaluate(ParentRunner.java:184) 
     at org.junit.runners.ParentRunner.run(ParentRunner.java:236) 
     at org.eclipse.jdt.internal.junit4.runner.JUnit4TestReference.run(JUnit4TestReference.java:49) 
     at org.eclipse.jdt.internal.junit.runner.TestExecution.run(TestExecution.java:38) 
     at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests(RemoteTestRunner.java:467) 
     at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests(RemoteTestRunner.java:683) 
     at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.run(RemoteTestRunner.java:390) 
     at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.main(RemoteTestRunner.java:197) 

如何在编写测试时解决此问题？

谢谢

固定！通过扩展FunctionalTest

public class PlaylistTest extends FunctionalTest { 

    @Test 
    @Transactional 
    public void insertIntoPlaylist() { 
     Playlist playlist = new Playlist(); 
     playlist.setName("new_playlist_again"); 

     EntityManager em = JPA.em(); 
     em.persist(playlist); 
    } 
} 

Answer 1

public class PlaylistTest extends FunctionalTest { 

    @Test 
    @Transactional 
    public void insertIntoPlaylist() { 
     Playlist playlist = new Playlist(); 
     playlist.setName("new_playlist_again"); 

     EntityManager em = JPA.em(); 
     em.persist(playlist); 
    } 
}