2
我正在开发一个新的模块,它将显示滑块上的特色项目。如何从Joomla的db中获取文章的图像路径
我已成功获取我的模块中的数据,但对于介绍图像有问题。
我的查询是在这里:
// Get a db connection.
$db = JFactory::getDbo();
// Create a new query object.
$query = $db->getQuery(true);
$query
->select(array('f.content_id', 'c.id', 'c.title', 'c.alias', 'c.images'))
->from('#__content AS c')
->join('INNER', '#__content_frontpage AS f ON (c.id = f.content_id)')
->where("c.language = '" . JFactory::getLanguage()->getTag() . "' AND c.state=1")
->order('f.ordering ASC');
// Reset the query using our newly populated query object.
$db->setQuery($query);
// Load the results as a list of stdClass objects.
$results = $db->loadObjectList();
foreach ($results as $r)
{
$imagePath = $r->images;
//.
//.
//.
}
正如你所知道的图像路径保存在images
列在目录类似以下形式:
{
"image_intro":"images\/products\/201191420496.jpg",
"float_intro":"",
"image_intro_alt":"",
"image_intro_caption":"",
"image_fulltext":"",
"float_fulltext":"",
"image_fulltext_alt":"",
"image_fulltext_caption":""
}
我想知道如何提取的介绍图像路径从这个数据。有没有一个共同的功能/方法呢,还是应该使用PHP的explode()
函数?