你会如何将这种多线失败转化为HAML？

Question

我无法完全理解这一点。

原文：

<%= 
Shasta::CSV.generate do |csv| 
    csv << ["Customer", "Job Name", "Payment Date", "Amount", "Notes"] 

    for payment in @payments 
    csv << [ 
     payment.customer.name, 
     payment.jobs.map(&:name).join(" "), 
     I18n.l(payment.created_at, :format => :short_date), 
     number_to_currency(payment.amount), 
     payment.notes 
    ] 
    end 
end.html_safe 
%> 

HTML2HAML它转换为这一点，但它失败

= Shasta::CSV.generate do |csv|          | 
    csv << ["Customer", "Job Name", "Payment Date", "Amount", "Notes"] | 
    for payment in @payments           | 
     csv << [               | 
     payment.customer.name,           | 
     payment.jobs.map(&:name).join(" "),       | 
     I18n.l(payment.created_at, :format => :short_date),   | 
     number_to_currency(payment.amount),       | 
     payment.notes             | 
     ]                | 
    end                | 
    end.html_safe              | 

Answer 1

这并不完全回答你的问题，但它是一个痛苦编写多行haml语句，这就是为什么你应该把它移入帮助程序。

= some_descriptive_method_name @payments

def some_descriptive_method_name(payments) 
    Shasta::CSV.generate do |csv| 
    csv << ["Customer", "Job Name", "Payment Date", "Amount", "Notes"] 

    payments.each do |payment| 
     csv << [ 
     payment.customer.name, 
     payment.jobs.map(&:name).join(" "), 
     I18n.l(payment.created_at, :format => :short_date), 
     number_to_currency(payment.amount), 
     payment.notes 
     ] 
    end 
    end.html_safe 
end