2012-06-03 75 views
0

对此问题进行了一点介绍,
在我发布此文档之前,我试图在google/stack上搜索这些内容,但大多数内容都不清楚。
我有一个基于cortex-a8的电路板,我正在其上运行裸机RTOS,显示器(framebuffer)有点慢,因为我目前还没有为我的目标实现DMA,但并不是那么慢,但是我注意到了一个改进的机会。在我的CPU和工具链组合中,32位数学运算,数据访问比16位访问快,显示器是16位rgb565,所以一些framebuffer操作比他们可能会慢一些(其中一些使用memcpy,memmove和memset,其中照顾数据对齐等)。在单个更大的数据类型中存储两种数据类型

我试图将两个像素塞进一个32位数据类型,并使用它来访问内存(对齐,据我记得,即使不,我的CPU在硬件中支持未对齐的内存访问,所以问题不应该是这样的)。请注意,我不是在谈论我的实现速度,而是我得到的一个奇怪的影响,我怀疑是因为我如何将两个像素塞入到一个32位数据类型。

这里是我的fb_putc

if (((unsigned char)c > 32) && ((unsigned char) c < 127)) { 
    check_for_scroll(49); 

    // fontdata starts from ASCII 33 shifted by logarithm(base2, font_height) 
    c -= 33; 
    c <<= 4; 

    uint16_t pallete_16[2] = {fb.fg_color, fb.tg_color}; 

    uint32_t y; 
    uint32_t *pixel_32; 
    uint32_t fb_shifter; 
    uint32_t pixel_32_holder; 
    uint32_t fb_bg_32 = ((pallete_16[1] << 16) | (pallete_16[1])); 
    /* 
    * Each pixel is 16 bits, we access them using 32 bit data type, 
    * which is faster for aligned memory access. Also many architectures 
    * have free bit shifts with each instruction so we use that too. 
    */ 
    pixel_32 = (uint32_t *) fb.config->base; 
    pixel_32 += (((fb.cursor.y * (FONT_HEIGHT * fb.config->width)) + ((fb.cursor.x * (FONT_WIDTH)))) 
        /((sizeof(uint32_t))/(sizeof(uint16_t)))); 
    for (y = 0; y < 16; y++) { 
     for (unsigned x = 7; x >= 0; x -= 2) 
     { 
      if (fontdata[c + y] & (1 << x)) { 
       pixel_32_holder = (pallete_16[0] << 16); 
      } else { 
       pixel_32_holder = (pallete_16[1] << 16); 
      } 
      if (fontdata[c + y] & (1 << (x -1))) { 
       pixel_32_holder |= (pallete_16[0] & 0xffff); 
      } else { 
       pixel_32_holder |= (pallete_16[1] & 0xffff); 
      } 
      *pixel_32++ = pixel_32_holder; 
     } 
     // Panel stride = width (480) - font_width (8) 
     pixel_32 += (472/((sizeof(uint32_t))/(sizeof(uint16_t)))); 
    } 

    fb.cursor.x++; 
} 

关于我哪里错了任何帮助的大部分?我对编程有点新,并且以此为爱好。

回答

1

你的想法在将它们写入存储器之前组合2个像素是正确的。 ARM的写缓冲硬件将以这种方式更高效地使用,代码运行速度更快。我不认为以这种形式混合C和ASM会产生最好的结果。坚持纯粹的ASM将保证你使用有条件执行的指令。另外,为调色板使用数组可能会导致编译器输出非常低效的代码。这是一种在纯ASM中更高效地执行此操作的方法。展开循环是一个好主意。这是处理双字节字体数据的每个字节的代码。

@ Register usage 
@ R0 = source data pointer 
@ R1 = destination data pointer 
@ R2 = foreground color (loaded outside of loop) 
@ R3 = background color (loaded outside of loop) 
@ R4,R5 = temp registers 
@ Assumes that the most significant short of each 32-bit word is on the left 

    ldrb r4,[r0],#1 @ source bitonal image data 
@ first pair of pixels 
    tst r4,#0x80 
    movne r5,r5,r2,LSL #16 
    moveq r5,r5,r3,LSL #16 
    tst r4,#0x40 
    orrne r5,r5,r2 
    orreq r5,r5,r3 
    str r5,[r1],#4 
@ second pair of pixels 
    tst r4,#0x20 
    movne r5,r5,r2,LSL #16 
    moveq r5,r5,r3,LSL #16 
    tst r4,#0x10 
    orrne r5,r5,r2 
    orreq r5,r5,r3 
    str r5,[r1],#4 
@ third pair of pixels 
    tst r4,#0x8 
    movne r5,r5,r2,LSL #16 
    moveq r5,r5,r3,LSL #16 
    tst r4,#0x4 
    orrne r5,r5,r2 
    orreq r5,r5,r3 
    str r5,[r1],#4 
@ fourth pair of pixels 
    tst r4,#0x2 
    movne r5,r5,r2,LSL #16 
    moveq r5,r5,r3,LSL #16 
    tst r4,#0x1 
    orrne r5,r5,r2 
    orreq r5,r5,r3 
    str r5,[r1],#4 

更新稍微简单的代码

+0

从我相信,第二个指令应该归零R5,但为什么呢?感谢您的帮助和努力。 – sgupta

+0

哦,明白了,所以你在使用r5来临时存储合并的结果之前..应该在写之前完全阅读。 再次感谢。 – sgupta

0

我已经修复了在过去几个小时内编译器吃掉我的头后,通过使用asm一次存储两个像素,但现在似乎还有一些其他问题,因为字符出现乱码,除了少数几个,我我不知道世界是什么原因造成这个...

至于包装中的像素,这是我最后使用的(只是柜面有人在未来可能需要这样做)

if (((unsigned char)c > 32) && ((unsigned char) c < 127)) { 

    check_for_scroll(FB_MAX_Y_UNDER); 

    uint32_t pixel_32_tmp; 
    uint16_t pallete[2] = { (fb.fg_color), (fb.tg_color)}; 
    uint32_t *pixel_32 = (uint32_t *)fb.base +((((fb.cursor.y << 13)-(fb.cursor.y << 9))+(fb.cursor.x << 3)) >> 1); 

    c -= 32; 
    c <<= 4; 

    for (int y = 0; y < 16; y++) { 
     unsigned char font_bits = fontdata[c + y]; 

     if (font_bits & 0x80) { 
      __asm__ volatile("mov %0, %1, lsl $16" : "=r" (pixel_32_tmp) : "r" (pallete[0])); 
     } else { 
      __asm__ volatile("mov %0, %1, lsl $16" : "=r" (pixel_32_tmp) : "r" (pallete[1])); 
     } 
     if (font_bits & 0x40) { 
      __asm__ volatile("orr %0, %0, %1" : "=r" (pixel_32_tmp) : "r" (pallete[0])); 
     } else { 
      __asm__ volatile("orr %0, %0, %1" : "=r" (pixel_32_tmp) : "r" (pallete[1])); 
     } 
     *pixel_32++ = pixel_32_tmp; 

     if (font_bits & 0x20) { 
      __asm__ volatile("mov %0, %1, lsl $16" : "=r" (pixel_32_tmp) : "r" (pallete[0])); 
     } else { 
      __asm__ volatile("mov %0, %1, lsl $16" : "=r" (pixel_32_tmp) : "r" (pallete[1])); 
     } 
     if (font_bits & 0x10) { 
      __asm__ volatile("orr %0, %0, %1" : "=r" (pixel_32_tmp) : "r" (pallete[0])); 
     } else { 
      __asm__ volatile("orr %0, %0, %1" : "=r" (pixel_32_tmp) : "r" (pallete[1])); 
     } 
     *pixel_32++ = pixel_32_tmp; 

     if (font_bits & 0x08) { 
      __asm__ volatile("mov %0, %1, lsl $16" : "=r" (pixel_32_tmp) : "r" (pallete[0])); 
     } else { 
      __asm__ volatile("mov %0, %1, lsl $16" : "=r" (pixel_32_tmp) : "r" (pallete[1])); 
     } 
     if (font_bits & 0x04) { 
      __asm__ volatile("orr %0, %0, %1" : "=r" (pixel_32_tmp) : "r" (pallete[0])); 
     } else { 
      __asm__ volatile("orr %0, %0, %1" : "=r" (pixel_32_tmp) : "r" (pallete[1])); 
     } 
     *pixel_32++ = pixel_32_tmp; 

     if (font_bits & 0x02) { 
      __asm__ volatile("mov %0, %1, lsl $16" : "=r" (pixel_32_tmp) : "r" (pallete[0])); 
     } else { 
      __asm__ volatile("mov %0, %1, lsl $16" : "=r" (pixel_32_tmp) : "r" (pallete[1])); 
     } 
     if (font_bits & 0x01) { 
      __asm__ volatile("orr %0, %0, %1" : "=r" (pixel_32_tmp) : "r" (pallete[0])); 
     } else { 
      __asm__ volatile("orr %0, %0, %1" : "=r" (pixel_32_tmp) : "r" (pallete[1])); 
     } 
     *pixel_32++ = pixel_32_tmp; 

     pixel_32 += 236; 
    } 
    fb.cursor.x++; 
}