Ruby hash delete_if许多

Question

Some_hash.delete_if {|key, value| key == "at" || key == "with" || key == "from"} 

我刚刚包括3个但我有一个7的列表，这条线变得很长很丑。有没有办法以更短的方式做到这一点，而不必每次都做key == SOMEVALUE？

Answer 1

SomeHash.except(:key1, :key2, ...) 

Rails有得心应手Hash#except扩展：

返回包含一切，但给定的密钥的哈希值。

Answer 2

%w[at with from] 
.each_with_object(Some_hash){|k, h| h.delete(k)} 

Answer 3

尝试：

keys_to_remove = ['at', 'with', 'from'] 
hash.delete_if {|key,_| keys_to_remove.include? key}