2015-08-27 55 views
1

我尝试过使用这个问题Setting up one to many relationship with Fluent Nhibernate作为基础,但仍然存在问题。保存子对象时流畅的NHibernate映射失败

我有两个类 - 联系人和PostalAddress - 联系人可以有很多地址。问题是当它到达一类具有的PostalAddress它失败

无效索引1这SqlParameterCollection以计数= 1。

有针对特定联系人地址

联系类

using System; 
using System.Collections.Generic; 
using System.Linq; 
using System.Runtime.Serialization; 
using System.Text; 
using System.Threading.Tasks; 

namespace YourLivesDataEngine.DataObjects 
{ 
    [DataContract()] 
    public class Contact 
    { 
     private String givenName; 
     private String surname; 
     private String middleName; 
     public Contact() 
     { 
      Emails    = new List<EmailAddress>(); 
      Addresses   = new List<PostalAddress>(); 
      TelephoneNumbers = new List<TelephoneNumber>(); 

      givenName   = String.Empty; 
      surname    = String.Empty; 
      middleName   = String.Empty; 

      Id     = Guid.NewGuid().ToString(); 
     } 
     [DataMember] 
     public virtual String Id { get; set; } 
     [DataMember] 
     public virtual DateTime LastUpdated { get; set; } 
     [DataMember] 
     public virtual String Network { get; set; } 
     [DataMember] 
     public virtual String NetworkId { get; set; } 
     [DataMember] 
     public virtual String Name { get; set; } 
     [DataMember] 
     public virtual String GivenName { get; set; } 
     [DataMember] 
     public virtual String Surname { get; set; } 
     [DataMember] 
     public virtual String MiddleName { get; set; } 
     [DataMember] 
     public virtual IList<EmailAddress> Emails { get; set; } 
     [DataMember(Name="Addresses")] 
     public virtual IList<PostalAddress> Addresses { get; set; } 
     [DataMember] 
     public virtual IList<TelephoneNumber> TelephoneNumbers { get; set; } 


    } 
} 

的PostalAddress类

public class PostalAddress 
{ 
    public PostalAddress() 
    { 
     Id = Guid.NewGuid().ToString(); 
    } 
    [DataMember] 
    public virtual String Id { get; set; } 
    public virtual String Address { get; set; } 
    public virtual String Owner { get; set; } 
    public virtual String AddressType { get; set; } 
    public virtual Contact Contact { get; set; } 
} 

我的映射

ContactMap

public class ContactMap : ClassMap<Contact> 
{ 
    public ContactMap() 
    { 
     Table("tblContacts"); 
     Id(x => x.Id); 
     Map(x => x.LastUpdated); 
     Map(x => x.Network); 
     Map(x => x.NetworkId); 
     Map(x => x.Name); 
     Map(x => x.GivenName); 
     Map(x => x.Surname); 
     Map(x => x.MiddleName); 

     HasMany<PostalAddress>(x => x.Addresses) 
      .Inverse() 
      .KeyColumns.Add("Id", mapping => mapping.Name("Id")) 
      .Cascade.SaveUpdate() 
    } 
} 

PostalAddressMap

public class PostalAddressMap 
     : ClassMap<PostalAddress> 
    { 
     public PostalAddressMap() 
     { 
      Table("tblPostalAddresses"); 
      Id(x => x.Id); 
      Id(x => x.Address); 
      Id(x => x.AddressType); 
      Id(x => x.Owner); 

      References(x => x.Contact) 
       .Class<Contact>() 
       .Column("Owner"); 

     } 
    } 

的代码保存联系人是

public void Save (Contact Contact) 
    { 
     try 
     { 
      using (ISessionFactory factory = CreateSessionFactory()) 
      { 
       using (var session = factory.OpenSession()) 
       { 
        using (ITransaction transaction = session.BeginTransaction()) 
        { 
         // save the contact 
         session.Save(Contact); 
         transaction.Commit(); 

        } 
       } 
      } 
     } 
     catch (System.Exception e) 
     { 
      throw e; 
     } 
     finally 
     { 

     } 

    } 

我敢肯定,这是值得做的方式映射设置但ca没有看到它,虽然有一些联系人没有地址 - 有些人这样做,我应该至少有一些地址。

+0

您是否通过PersistenceSpecification测试人员验证了您的地图?不要在我附近有VS,所以语法可能会关闭:https://gist.github.com/mxmissile/d81682def1d88a522767 – mxmissile

+0

不 - 我刚刚通过在PostalAddressMap中提及所有者的注释掉了问题中的错误。现在它不会将Id写入PostalAddress记录,因此如果将Id设置为null(由于它是主键而不允许),因此不允许为null。 –

+0

首先,您的PostalAddressMap是错误的,您将属性映射为Id。 – mxmissile

回答

0

在mxmissile的帮助下,现在已经修复了它。

问题都出现在PostalAddress的映射中。首先,我制作了所有的字段Id - 将所需的属性更改为Map。

然后,我每次尝试保存地址时都得到了这个SqlParameterCollection的Count = 4错误的无效索引4。当一个字段被映射两次时会导致此错误。对于这个映射,它是被映射了两次的所有者。它不需要在地图中列出 - 通过评论它的应用程序工作。修改后的Mapping类如下所示;

public class PostalAddressMap 
    : ClassMap<PostalAddress> 
{ 
    public PostalAddressMap() 
    { 
     Table("tblPostalAddresses"); 
     Id(x => x.Id); 
     Map(x => x.Address); 
     Map(x => x.AddressType); 

     References(x => x.Contact) 
      .Class<Contact>() 
      .Column("Owner"); 

    } 
} 

一旦进行了这些更改,应用程序就会正确保存联系人和地址。

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