尝试通过php表单提交更新MySQL中的记录,但我不断收到错误:MySQL无法更新记录
更新记录时出错:您的SQL语法错误;检查对应于你的MySQL服务器版本正确的语法使用近“SET手机=” 3609992399' ,地址=‘123试验巷’,城市=‘战役的Gr’在行手动4
if (isset($_POST['submit'])) {
$first_name = $_POST['first_name'];
$last_name = $_POST['last_name'];
$email = $_POST['email'];
$phone = $_POST['phone'];
$address = $_POST['address'];
$city = $_POST['city'];
$state = $_POST['state'];
$zipcode = $_POST['zipcode'];
$mysqli = new mysqli($DB_HOST, $DB_USER, $DB_PASS, $DB_NAME);
if ($mysqli->connect_errno) {
echo "<p>MySQL error no {$mysqli->connect_errno} : {$mysqli->connect_error}</p>";
exit();
} else {
$updateUser = "UPDATE users SET first_name='{$first_name}', last_name='{$last_name}', email='{$email}', phone='{$phone}', address='{$address}', city='{$city}', state='{$state}', zipcode='{$zipcode}' WHERE vendorid='{$user['vendorid']}'";
if ($mysqli->query($updateUser) === TRUE) {
echo "Record updated successfully";
} else {
echo "Error updating record: " . $mysqli->error;
}
}
$mysqli->close();
}
伊夫检查5.5的文件,一切看起来都很合适。任何线索?
在查询中不需要大括号,只需调用一次即可。 – quid 2014-12-04 21:54:04
只有一个** SET **需要,所以只保留其余的第一个删除 – 2014-12-04 21:55:39
@quid大括号与问题无关。它们是有效的。 – 2014-12-04 21:58:40