Android的SQLite：光标索引出界

Question

你好我得到一个OutOfBoundsExpection：索引0请求，大小为0.我的数据库以前工作。

下面是代码片段：

MainActivity.db = new DatabaseHandler(ncontext); 
MainActivity.db.addPokemon(new Pokedex(0, "Bulbasaur", "001", "Grass/Poison", "Lv 5",1)); 

//Crashes: 
Log.d(tag,"This is drawable: "+ MainActivity.db.getPokemon(0,1).getPokemonImage()); 

//DataBase class 

     SQLiteDatabase db = this.getReadableDatabase(); 

     Cursor cursor = db.query(TABLE_POKEMON, columns, KEY_ID + "=?" + " AND " 
       + KEY_POKEMON_IMAGE + "=?", new String[] { String.valueOf(id), 
       String.valueOf(poke_image) }, null, null, null, null); 
     if ((cursor != null && cursor.moveToFirst())){ 
      cursor.moveToNext(); 
      cursor.close(); 
     } 
     Log.d(Tag, "pre pokedex fetch"); 
     Pokedex pokemon; 

     //CRASHES 
     Log.d("Database","1: " + Integer.parseInt(cursor.getString(0))); 
     // return pokemon 
     pokemon = new Pokedex(Integer.parseInt(cursor.getString(0)), 
       cursor.getString(1), cursor.getString(2), cursor.getString(3), 
       cursor.getString(4), Integer.parseInt(cursor.getString(5))); 
     Log.d(Tag, "getPokemon done"); 
     return pokemon; 

任何想法是怎么回事？

Answer 1

您正在关闭光标并将光标移动到下一个位置，而不处理if条件内的第一个结果集。像下面

if ((cursor != null && cursor.moveToFirst())){ 

     Log.d(Tag, "pre pokedex fetch"); 
     Pokedex pokemon; 

     //CRASHES 
     Log.d("Database","1: " + Integer.parseInt(cursor.getString(0))); 
     // return pokemon 
     pokemon = new Pokedex(Integer.parseInt(cursor.getString(0)), 
       cursor.getString(1), cursor.getString(2), cursor.getString(3), 
       cursor.getString(4), Integer.parseInt(cursor.getString(5))); 
     Log.d(Tag, "getPokemon done"); 
     return pokemon; 
     cursor.close(); 
}