我曾经有过同样的问题。您可以解压缩xlsx并读取/解释xml文件。这两个更重要的文件就是这些。
- XL/pivotCache/pivotCacheDefinition1.xml
- XL/pivotCache/pivotCacheRecords1.xml
第一个,在pivotCacheRecords1.xml原始数据的relationshit,你需要访问通过索引号,我的意思是,通过pivotCacheRecords1.xml中的每个列都有标记<x>
,您需要通过标记<x>
的索引号获取pivotCacheDefinition1.xml中的数据,为了更好地理解,您需要请参阅xml文件。
pivotCacheDefinition1.xml
<?xml version="1.0" encoding="UTF-8"?>
<pivotCacheDefinition xmlns="http://schemas.openxmlformats.org/spreadsheetml/2006/main" xmlns:r="http://schemas.openxmlformats.org/officeDocument/2006/relationships" r:id="rId1" refreshedBy="ADNLatam" refreshedDate="42972.64919178241" createdVersion="5" refreshedVersion="6" recordCount="1923161">
<cacheSource type="external" connectionId="1" />
<cacheFields count="26">
<cacheField name="C - Cadenas" numFmtId="0" sqlType="-9">
<sharedItems count="3">
<s v="superA" />
<s v="superB" />
<s v="superC" u="1" />
</sharedItems>
</cacheField>
<cacheField name="C - Locales" numFmtId="0" sqlType="-9"><span data-mce-type="bookmark" style="display: inline-block; width: 0px; overflow: hidden; line-height: 0;" class="mce_SELRES_start"></span>
<sharedItems count="80">
<s v="Itaugua" />
<s v="Denis Roa" />
<s v="Total" />
<s v="Los Laureles" />
<s v="CDE" />
<s v="S6 Fdo." />
<s v="Central" u="1" />
<s v="Unicompra" u="1" />
<s v="San Lorenzo Centro" u="1" />
</sharedItems>
</cacheField>
</cacheFields>
</pivotCacheDefinition>
</xml>
pivotCacheRecords1.xml
<pivotCacheRecords
xmlns="http://schemas.openxmlformats.org/spreadsheetml/2006/main"
xmlns:r="http://schemas.openxmlformats.org/officeDocument/2006/relationships" count="246209">
<r>
<x v="0"/>
<x v="0"/>
<x v="0"/>
<x v="0"/>
<s v="PAÐAL "PAMPERS" BABYSAN REGULAR GDE 9UN"/> #Z - Sku/Descripcion
<s v="07501006720341"/>
<x v="0"/>
<x v="0"/>
<x v="0"/>
<x v="0"/>
<x v="0"/>
<x v="0"/>
<n v="1"/>
<n v="11990"/>
<n v="2.3199999999999998"/>
<n v="10900"/>
<n v="11990"/>
<n v="1"/>
<d v="2012-02-03T00:00:00"/>
<x v="0"/>
<x v="0"/>
<n v="3"/>
<n v="6"/>
<x v="0"/>
<x v="0"/>
<x v="0"/>
<x v="0"/>
<x v="0"/>
<x v="0"/>
</r>
看到,在CacheRecords1标签<x>
是在CacheDefinition1的<s>
标签的关系,现在如果你明白的话这对于在记录的迭代中使用它来说并不那么困难。
definitions = '/tmp/scantrack_tmp/xl/pivotCache/pivotCacheDefinition1.xml'
defdict = {}
columnas = []
e = xml.etree.ElementTree.parse(definitions).getroot()
for fields in e.findall('{http://schemas.openxmlformats.org/spreadsheetml/2006/main}cacheFields'):
for cidx, field in enumerate(fields.getchildren()):
columna = field.attrib.get('name')
defdict[cidx] = []
columnas.append(columna)
for value in field.getchildren()[0].getchildren():
tagname = value.tag
defdict[cidx].append(value.attrib.get('v', 0))
我们结束了这个字典。
{
0: ['supera', 'superb', u'superc'],
1: ['Terminal',
'CDE',
'Brasilia',
]
3: ['PANTENE', 'DOVE']
...
}
然后你有待办事项被遍历CacheRecords1和列的索引与defdict的密钥相匹配时,标签是<x>
dfdata = []
bdata = '/tmp/scantrack_tmp/xl/pivotCache/pivotCacheRecords1.xml'
for event, elem in xml.etree.ElementTree.iterparse(bdata, events=('start', 'end')):
if elem.tag == '{http://schemas.openxmlformats.org/spreadsheetml/2006/main}r' and event == 'start':
tmpdata = []
for cidx, valueobj in enumerate(elem.getchildren()):
tagname = valueobj.tag
vattrib = valueobj.attrib.get('v')
rdata = vattrib
if tagname == '{http://schemas.openxmlformats.org/spreadsheetml/2006/main}x':
try:
rdata = defdict[cidx][int(vattrib)]
except:
logging.error('this it not should happen index cidx = {} vattrib = {} defaultidcts = {} tmpdata for the time = {} xml raw {}'.format(
cidx, vattrib, defdict, tmpdata,
xml.etree.ElementTree.tostring(elem, encoding='utf8', method='xml')
))
tmpdata.append(rdata)
if tmpdata:
dfdata.append(tmpdata)
elem.clear()
然后你就可以在数据帧放dfdata
df = pd.DataFrame(dfdata).
其余的是历史,我希望这会帮助你。
快乐编码!
正确。但是有一个细节:如果数据透视表数据是隐藏的(只有摘要显示在表中),它可能不在同一张表中,而在数据对象中。在这种情况下,可以很容易地用例如数据提取xml数据。方舟(解压xlsx) – 2017-08-10 07:47:30