grails XML to Object绑定

是否有一个grails插件或库可以将XML数据映射到Java类Object中？grails XML to Object绑定

我正在寻找一些将xml数据映射到Java类字段的groovy类。

--- UPDATE -----

以下的Grails服务类尝试做这个映射，但它不工作。

会有人提示如何纠正下面的代码，使其工作？

感谢

class DataBinderService { 

boolean transactional = false 
def grailsApplication 
private BeanWrapper wrapper = new BeanWrapperImpl() 

public List bindAllXmlData (Class targetClass, GPathResult source, List properties) { 
    if (targetClass == null || source == null || properties == null) return null 
    def resultList = [] 
    def className = WordUtils.uncapitalize(targetClass.simpleName) 
    source[className]?.each { 
     def boundObj = bindXmlData(targetClass, it, properties) 
     System.out.println(boundObj) 
     resultList.add(boundObj) 
    } 
    return resultList 
} 

public Object bindXmlData (Class targetClass, GPathResult source, List properties) { 
    if (targetClass == null || source == null || properties == null) return null 
    def targetObject = grailsApplication.classLoader.loadClass(targetClass.name).newInstance() 
    if (targetObject) { 
     return bindXmlData(targetObject, source, properties) 
    } else { 
     return null 
    } 
} 

public Object bindXmlData (Object target, GPathResult source, List properties) { 
    if (target == null || source == null || properties == null) return null 
    wrapper.registerCustomEditor (Date.class, new CustomDateBinder()) 
    wrapper.setWrappedInstance(target) 
    properties.each {String property -> 
     if (property.contains('.')) {//This indicates a domain class to bind e.g. experiment.id -> Experiment 
      def propertyName = property.tokenize('.') 
      def id = source[propertyName[0]]["@${propertyName[1]}"]?.toString() 
      if (id != null) { 
       def subdomainInstance = null 
       try {subdomainInstance = grailsApplication.classLoader.loadClass("edu.kit.iism.experimentcenter.${WordUtils.capitalize(propertyName[0])}").get(id)} catch (Exception ex) {} 
       if (subdomainInstance != null) wrapper.setPropertyValue(propertyName[0], subdomainInstance) 
      } 
     } else if (property.equals('id')) { //The id property is set as an attribute rather than text 
      def id = source['@id']?.toString() 
      if (id != null) wrapper.setPropertyValue(property, id) 
     } else { //regular attributes 
      def prop = source[property]?.toString() 
      if (prop != null) wrapper.setPropertyValue(property, prop) 
     } 
    } 
    return target 
}

}

来源

2012-07-04 othman

Groovy的'XMLSlurper'是不够的？ – Grooveek

它不是通用和通用的。我们需要手动解析xml并保存到Java对象。对？我需要的是一个通用的方法来自动绑定一个Java类与XML数据 – othman

我已经更新了OP。有一个班我尝试做绑定。但它不起作用。 – othman

您可以使用西河了点。检查这篇文章我写

http://moskiteau.tumblr.com

来源

2012-07-04 18:12:31 moskiteau

这真的是非常好的文章。正是我在找什么。我会试一试XStream。谢谢！ – othman

在您的文章中突出显示的语法是可怕的... – rdmueller

grails XML to Object绑定

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