2011-05-30 61 views
26

我已经实体,称为客户,它有三个属性:内加入LINQ到实体

public class Customer { 
    public virtual Guid CompanyId; 
    public virtual long Id; 
    public virtual string Name; 
} 

我还实体,称为分裂,它有三个属性:

public class Splitting { 
    public virtual long CustomerId; 
    public virtual long Id; 
    public virtual string Name; 
} 

现在我需要编写一个获取companyId和customerId的方法。该方法应返回与companyId中特定customerId相关的拆分清单。 事情是这样的:

public IList<Splitting> get(Guid companyId, long customrId) {  
    var res=from s in Splitting 
      from c in Customer 
      ...... how to continue? 

    return res.ToList(); 
} 
+0

在地方分割您粘贴Customer实体的两倍。请修复 – Ankur 2011-05-30 12:20:01

+0

@Ankur:用鼠标右键 - 谢谢! – Naor 2011-05-30 12:21:38

+0

为什么你需要公司ID在方法get ...分裂有客户ID可用于根据传递的客户ID进行选择 – Ankur 2011-05-30 12:28:52

回答

69
var res = from s in Splitting 
      join c in Customer on s.CustomerId equals c.Id 
     where c.Id == customrId 
      && c.CompanyId == companyId 
     select s; 

使用Extension methods

var res = Splitting.Join(Customer, 
       s => s.CustomerId, 
       c => c.Id, 
       (s, c) => new { s, c }) 
      .Where(sc => sc.c.Id == userId && sc.c.CompanyId == companId) 
      .Select(sc => sc.s); 
+1

有没有办法将其写入lambda查询? – Naor 2011-05-30 12:35:56

+2

如果你的意思是linq扩展方法('Select','Join' ...看我的编辑) – manji 2011-05-30 12:47:28

2

没有100%地肯定这两个实体,但这里的关系有云:

IList<Splitting> res = (from s in [data source] 
         where s.Customer.CompanyID == [companyID] && 
           s.CustomerID == [customerID] 
         select s).ToList(); 

IList<Splitting> res = [data source].Splittings.Where(
          x => x.Customer.CompanyID == [companyID] && 
           x.CustomerID == [customerID]).ToList(); 
5

你可以找到视觉工作室中的一大堆Linq例子。 只需选择Help -> Samples,然后解压Linq示例。

打开LINQ样品溶液,然后打开LinqSamples.cs的SampleQueries项目

你正在寻找的答案是方法Linq14:

int[] numbersA = { 0, 2, 4, 5, 6, 8, 9 }; 
int[] numbersB = { 1, 3, 5, 7, 8 }; 

var pairs = 
    from a in numbersA 
    from b in numbersB 
    where a < b 
    select new {a, b}; 
+1

我从来不知道直接在VS中获取样本。 +1 – ShooShoSha 2016-12-21 21:21:35

1
public IList<Splitting> get(Guid companyId, long customrId) {  
    var res=from c in Customers_data_source 
      where c.CustomerId = customrId && c.CompanyID == companyId 
      from s in Splittings_data_srouce 
      where s.CustomerID = c.CustomerID 
      select s; 

    return res.ToList(); 
}