把double值2d数组读取文本

Question

我想把我的文本的double值放在2d数组上。我的文字有这样的

我的文字从字符串

deneme deneme 4.5 5.5 6.6 7.5 9.9 9.9 

dsdsa sddsf 9.9 8.7 7.5 8.8 4.4 6.5 

ıextraxt双重价值双倍和字符串值。 我的节目输出为

4.5 5.5 6.6 7.5 9.9 9.9 9.9 8.7 7.5 8.8 4.4 6.5 

我该怎么办我的输出六重奏。如果我能做到这一点，我将整理每行

FIRSTLINE：4.5 5.5 6.6 7.5 9.9 9.9

二线：9.9 8.7 7.5 8.8 4.4 6.5

public static void main(String[] args) throws IOException { 

    ArrayList<String> puan; 
    puan = okuDiziyeKoy("C:\\deneme\\HW.txt"); 
    System.out.format("%d kayıt okundu.%n", puan.size()); 

    for (int j = 0; j < puan.size(); j++) { 

     String point = puan.get(j); 

     String[] edit = point.split("[\\{\\}\\)]"); 

     for (String s : edit) { 

      String a = s.replaceAll("[\\}\\-\\>\\>\\]\\[\\#\\*\\{]+", ""); 
      String b = a.replaceAll("[\\.]+", ","); 
      Scanner scanner = new Scanner(b); 

      while (scanner.hasNext()) { 

       if (scanner.hasNextDouble()) { 

        Double doubleValue = scanner.nextDouble(); 
        List<Double> numbers = new ArrayList<Double>(); 
        numbers.add(doubleValue); 
        // System.out.println(Arrays.deepToString(numbers.toArray())); 

        final int col = 6; 
        final int rows = numbers.size() % col == 0 ? numbers.size()/col : numbers.size()/col + 1; 
        double[][] deneme = new double[rows][col]; 
        for (int i = 0; i < rows; i++) { 
         for (int k = 0; k < col; k++) { 
          if (i == rows - 1 && k >= numbers.size() % col) 
           break; 
          deneme[i][k] = numbers.get(k + col * i);  
          System.out.print(deneme[i][k]+ " "); 
         }// for k end 
         System.out.println(); // go to next line 
        } // for i end 

       }// if scan end 

       else { 

        //if it is string comes value here 
        String stringValue = scanner.next(); 

       }// if scan end 

      }// while end 

     }// for string s 

    }// for end 

}// main end 

Answer 1

当还原元素融入deneme，所有的元素会因为k投入deneme[0]从0到numbers.size() - 1。您可以修复它，如下所示：

final int col = 6; 
final int rows = numbers.size() % col == 0 ? numbers.size()/col : numbers.size()/col + 1; 
double[][] deneme = new double[rows][col]; 
for (int i = 0; i < rows; i++) { 
    for (int k = 0; k < col; k++) { 
     if (i == rows - 1 && k >= numbers.size() % col) // UPDATE: last line may not contain `col` sized elements 
      break; 
     deneme[i][k] = numbers.get(k + col * i);  
     System.out.print(deneme[i][k]+ " "); 
    }// for k end 
    System.out.println(); // go to next line 
} // for i end 

Answer 2

介绍一个新行内循环后（ k loop），请使用System.out.println()。

for (int i = 0; i < numbers.size(); i++) { 
     for (int k = 0; k < numbers.size(); k++) { 
     deneme[i][k] = numbers.get(k + (numbers.size() * i));  
     System.out.print(deneme[i][k]+ " "); 
     }// for k end 
     System.out.println(); // to introduce a newline 
} // for i end