2016-05-22 139 views
-1

我想创建一个触发器,但在某处出现错误,我不知道如何编写正确的。Mysql创建触发器

CREATE TABLE IF NOT EXISTS Authorization(
userID INT PRIMARY KEY AUTO_INCREMENT, 
login VARCHAR(50) NOT NULL, 
password VARCHAR(64) NOT NULL, 
numberOfFailedAttempts SMALLINT, 
lastLogin TIMESTAMP, 
lockedAccount BOOLEAN 
); 


INSERT INTO Authorization SELECT NULL, "test1", SHA2('pass1', 256), 1, NULL, FALSE; 
INSERT INTO Authorization SELECT NULL, "test2", SHA2('pass2', 256), 1, NULL, FALSE; 
INSERT INTO Authorization SELECT NULL, "test3", SHA2('pass3', 256), 1, NULL, FALSE; 
INSERT INTO Authorization SELECT NULL, "test4", SHA2('pass4', 256), 1, NULL, FALSE;</code> 

我想创建一个触发器,当更新用户检查numberOfFailedAttempts。如果numberOfFailedAttempts> 3,则将lockedAccount更改为true。

CREATE TRIGGER trigger1 AFTER UPDATE ON `numberOfFailedAttempts` 
FOR EACH ROW 
BEGIN 
IF (`numberOfFailedAttempts` > 3) THEN 
UPDATE SET `lockedAccount` = 1 WHERE 1, LIMIT 1; 
END; 

的错误是:

#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near 'SET `lockedAccount` = 1 WHERE 1, LIMIT 1' at line 5</code> 

有人可以帮我吗?

编辑:

在这段代码中我有同样的错误。

CREATE TRIGGER trigger1 AFTER UPDATE ON `numberOfFailedAttempts` 
FOR EACH ROW 
BEGIN 
IF (`numberOfFailedAttempts` > 3) THEN 
UPDATE `Authorization` SET `lockedAccount` = '1' WHERE  `Authorization`.`userID` = OLD.`userID`; 
END; 

编辑:

我改变代码和它的工作。

delimiter // 

CREATE TRIGGER trigger1 BEFORE UPDATE ON Authorization 
FOR EACH ROW 
IF NEW.`numberOfFailedAttempts` > 3 THEN 
SET NEW.`lockedAccount` = 1; 
END IF;// 
+1

错误表明,你需要UPDATE'语句后'指定表名 –

+0

感谢您的答复,但在代码中仍然有同样的错误。 CREATE TRIGGER TRIGGER1 UPDATE ON Authorization.numberOfFailedAttempts FOR EACH ROW 之后开始 IF('numberOfFailedAttempts'> 3)THEN UPDATE SET OLD.'lockedAccount' = 1 WHERE 1,LIMIT 1; END; – pawel112

+0

您在错误的地方设置了表名,试试这个:UPDATE授权SET lockedAccount = 1 WHERE 1,LIMIT 1;' –

回答

0

希望它会为你工作。

DELIMITER // 

    CREATE TRIGGER trigger_name AFTER UPDATE ON Authorization 
    FOR EACH ROW 
    BEGIN 
     IF (numberOfFailedAttempts > 3) THEN 
      UPDATE Authorization SET lockedAccount = 1 WHERE 1 LIMIT 1; 
     END IF; 
    END // 

DELIMITER ; 
-1
CREATE TRIGGER trigger1 AFTER UPDATE ON `numberOfFailedAttempts` 
FOR EACH ROW 
BEGIN 
IF (`numberOfFailedAttempts` > 3) THEN 
UPDATE Authorization SET `lockedAccount` = 1 WHERE 1, LIMIT 1; 
END; 
+0

感谢您的回复,但我在第5行发生了错误。 – pawel112