Jquery .when（）不等待

Question

我试图根据Backbone.js中的国家/地区代码验证电话号码。我需要等到ajax回调被执行之后才返回验证结果。我正在使用Jquerys when方法。该模型的验证功能：

validate: function(attrs) { 

     this.errors = []; 


     if(attrs['phone'].length>0){ 
      //validate 

      console.log('before when '); 

      $.when(this.checkPhoneNumber(attrs)).done(function(response){ 

       console.log('resspone is '); 
       console.log(response); 

       if(response.valid!==true){ 
        that.errors.push({input_tag: 'phone', error: 'Please enter a valid phone number'}); 
       } 

       if(that.errors.length > 0){     
        return that.errors; 
       } 

      }); 

      console.log('after when '); 


     } 
     else{ 

      console.log('in the else so no phone number'); 

      if(this.errors.length > 0){ 
       return this.errors; 
      } 
     } 

    },   

而且checkPhoneNumber是：

checkPhoneNumber: function(attrs){ 

      return $.ajax({ 
       url: "http://hidden-oasis-1864.herokuapp.com/check-phone-number/"+attrs['country']+"/"+attrs['phone'], 
       success: function(response){ 

        console.log('in checkPhoneNumber success'); 

       }, 
       error: function(){ 

        that.errors.push({input_tag: 'phone', error: 'There was an error validating the phone number'}); 
        return that.errors; 
       } 
      });  

    }, 

在视图中，我做的：

 if (!this.model.isValid()) {   
      this.processErrors(this.model.validationError); 
     } 

isValid（）运行模型的validate（）methos。

但在日志中我总是得到：

before when ContactModel.js:46 

after when ContactModel.js:63 

MODEL IS VALID ContactItem.js:66 

in checkPhoneNumber success 

所以当（）不候。我究竟做错了什么？

Answer 1

尝试用

checkPhoneNumber: function(attrs){ 

     return $.ajax({ 
      url: "http://hidden-oasis-1864.herokuapp.com/check-phone-number/"+attrs['country']+"/"+attrs['phone'], 
      success: function(response){ 

       console.log('in checkPhoneNumber success'); 

      }, 
      error: function(){ 
       console.log("I FOUND MY PROBLEM"); 

       that.errors.push({input_tag: 'phone', error: 'There was an error validating the phone number'}); 
       return that.errors; 
      } 
     });  

}, 

它看起来像Ajax调用返回一个错误，所以done不会被调用。

要注册失败的回叫，请使用fail并注册回叫以始终执行使用then。