按ID和日期分组，但每个组的日期？

Question

我有这个疑问：两列的

declare @values table 
(
    Id int, 
    Dept varchar(1), 
    CounterL int, 
    CounterU int, 
    InsertDate datetime 
) 
insert into @values 
select 1, 'L', 5, null, '2017-10-28 4:00:00.000' 
union 
select 1, 'L', 8, null, '2017-10-28 4:00:00.000' 
union 
select 1, 'U', null, 30, '2017-10-28 3:00:00.000' 
union 
select 1, 'U', null, 40, '2017-10-28 3:00:00.000' 


select id, sum(counterl), sum(counteru) from @values 
where (datepart(hh, insertdate) = 4 or datepart(hh, insertdate) = 3) 
group by id, cast(InsertDate as date) 

下收益的总和，但我希望能够包括这些分组的日期。

的例子会是这个样子：

id ColumnL, ColumnU, Date   ValueU     ValueL 
1 13  70  2017-10-28 '2017-10-28 3:00:00.000' '2017-10-28 4:00:00.000' 

总会有一天两个小时，无论是HR 3或4

感谢。

Answer 1

这不够吗？

select id, sum(counterl), sum(counteru), cast(InsertDate as date) as dte 
from @values v 
where datepart(hour, insertdate) in (3, 4) 
group by id, cast(InsertDate as date); 

我的意思是，你还可以添加时间：

select id, sum(counterl), sum(counteru), cast(InsertDate as date) as dte, 
     dateadd(hour, 3, cast(InsertDate as date)), 
     dateadd(hour, 4, cast(InsertDate as date)) 
from @values v 
where datepart(hour, insertdate) in (3, 4) 
group by id, cast(InsertDate as date); 

，但似乎没有必要。

请注意，我用一个in替换了or表达式。而且，我已经写出了hour，所以代码更易于阅读。

编辑：

基于您的评论，你想有条件聚集：

select id, sum(counterl), sum(counteru), cast(InsertDate as date) as dte, 
     min(case when dept = 'L' then InsertDate end) as l_insertdate, 
     min(case when dept = 'U' then InsertDate end) as u_insertdate 
from @values v 
where datepart(hour, insertdate) in (3, 4) 
group by id, cast(InsertDate as date); 

Answer 2

SELECT DISTINCT Id, 
       SUM(CounterL) OVER(PARTITION BY ID, CAST(InsertDate AS DATE)) AS [ColumnL], 
       SUM(CounterU) OVER(PARTITION BY ID, CAST(InsertDate AS DATE)) As [ColumnU], 
       CAST(InsertDate AS DATE) [Date],    
       DATEADD(HOUR, 3-DATEPART(HOUR, InsertDate), InsertDate) AS [ValueU], 
       DATEADD(HOUR, 4-DATEPART(HOUR, InsertDate), InsertDate) AS [ValueL] 
FROM @values 
WHERE DATEPART(HH, INSERTDATE) IN (3,4)