我有这样的代码:PHP,通过关键字搜索的MySQL从多个表
function search_keyword(){
$keyword = trim($_POST['keyword']);
$search_explode = explode(" ", $keyword);
$x = 0;
$sql = " (SELECT name AS type FROM global_info WHERE ";
foreach($search_explode as $each){
$x++;
if($x == 1){
$sql .= " name LIKE '%$each%'";}
else {
$sql .= " name LIKE '%$each%' ";
}
}
$sql .= ") UNION ALL ";
$sql .= " (SELECT name AS type FROM person WHERE ";
foreach($search_explode as $each){
$x++;
if($x == 1){
$sql .= " name LIKE '%$each%'";}
else {
$sql .= " name LIKE '%$each%' ";
}
}
$sql .= ") UNION ALL ";
$sql .= "(SELECT name AS type FROM event WHERE ";
foreach($search_explode as $each){
$x++;
if($x == 1){
$sql .= " name LIKE '%$each%'";}
else {
$sql .= " name LIKE '%$each%' ";
}
}
$sql .= ") ";
$q = $this->db->query($sql);
return $q = $q->num_rows() == 0 ? FALSE : $q->result();
}
的功能正在工作。我不知道的是如何知道哪些数据来自哪个表格,然后在页面上显示结果?
它正在工作。感谢您的帮助 :) – Sasha 2012-03-29 10:50:57