2013-10-04 65 views
1

我正在尝试使用JWPlayer在我的网站上播放视频。但我不能得到从PHP的视频中投放动态,因为我发现了以下错误:JW Player从php读取无法动态地读取视频

Error loading media: File could not be played

我当前的代码是:

<?php 
    include('connection.php');//connect to db 
    $id = $_GET['id'];//get video id from param 
    $video = mysql_query("SELECT * FROM video_table WHERE id = '$id'");//video row from db 
    $data = mysql_fetch_assoc($video); 
    $ext = pathinfo($data['video_name'], PATHINFO_EXTENSION); 
    $file_name = $id . "." . $ext; 
    echo $file_name; 
?> 
    <div id="container1"></div> 
     <script type="text/javascript"> 
      jwplayer('container1').setup({ 
       'id': 'container1', 
       'type': '<?php echo $ext ?>', 
       'wmode': 'transparent', 
       'flashplayer': 'jwplayer/jwplayer.flash.swf', 
       'file': 'video.php', 
       'provider': 'video', 
       'width': '480', 
       'height': '320', 
      }); 
     </script> 
    </div> 

video.php

<?php 
    include('connection.php'); 
    $id = $_GET['id']; 
    $video = mysql_query("SELECT * FROM video_table WHERE id = '$id'"); 
    $data = mysql_fetch_assoc($video); 
    $ext = pathinfo($data['video_name'], PATHINFO_EXTENSION); 
    $type = pathinfo($data['type'], PATHINFO_EXTENSION); 
    $file_name = $id . "." . $ext;//set the file name as saved in upload directory e.g: 1.mp4 

    header("pragma : no-cache"); 
    header("Cache-Control: no-store, no-cache, must-revalidate, post-check=0, pre-check=0"); 
    header("Content-Description: File Transfer"); 
    header("Content-Type: $type"); 
    header("Content-Location: upload/$file_name"); 
    header("Content-Transfer-Encoding: binary"); 
    header("Content-Length: ".filesize("upload/$file_name")); 
    readfile("upload/$file_name"); 
?> 

但是,如果我在这里更改绝对名称(upload/1.mp4) instead of (upload/$file_name)它可以工作并提供视频。我如何从参数中动态获取视频?

回答

1

变化:

'provider': 'video', 

要:

'type': 'mp4', 

如果您使用FLV,而不是MP4,使其:

'type': 'flv', 

另外:

有几件事情这里。你仍然有供应商设置为视频,我会删除它。另外,你正在将文件作为video.php,但没有设置ID。现在你正在使用 - 'file':'video.php',我会将其更改为video.php?id = 1,我也会从6.4更新到6.6。

+0

我有'type':'<?php echo $ ext?>',其结果为视频类型(mp4或flv)。我仍然遇到同样的错误。我试图删除提供商,或更改为键入:mp4,但我得到相同的错误 – fareed

+0

我可以看到一个链接? – emaxsaun

+0

以下是使用上面相同代码的示例应用的链接http://fareed.comule.com/PhpProject1/view.php?id=1 – fareed