2015-05-14 85 views
1

我正在重新编写一个我已经创建的web服务,以便我可以用git为将要接管的我的组的其他成员创建一个“how-to”该项目。为servlet Jersey REST服务分配异常

这一次,我尝试使用我的webservice时开始出现错误,我似乎无法找到问题,因为代码看起来与我以前编写的代码(工作代码)完全相同。

我使用apache tomcat和Jersey与JSON。

以下是错误:

mai 14, 2015 6:08:02 PM org.apache.catalina.core.StandardWrapperValve invoke SEVERE: Allocate exception for servlet Jersey REST Service com.sun.jersey.api.container.ContainerException: The ResourceConfig instance does not contain any root resource classes. at com.sun.jersey.server.impl.application.RootResourceUriRules.<init>(RootResourceUriRules.java:99) at com.sun.jersey.server.impl.application.WebApplicationImpl._initiate(WebApplicationImpl.java:1359) at com.sun.jersey.server.impl.application.WebApplicationImpl.access$700(WebApplicationImpl.java:180) at com.sun.jersey.server.impl.application.WebApplicationImpl$13.f(WebApplicationImpl.java:799) at com.sun.jersey.server.impl.application.WebApplicationImpl$13.f(WebApplicationImpl.java:795) at com.sun.jersey.spi.inject.Errors.processWithErrors(Errors.java:193) at com.sun.jersey.server.impl.application.WebApplicationImpl.initiate(WebApplicationImpl.java:795) at com.sun.jersey.server.impl.application.WebApplicationImpl.initiate(WebApplicationImpl.java:790) at com.sun.jersey.spi.container.servlet.ServletContainer.initiate(ServletContainer.java:509) at com.sun.jersey.spi.container.servlet.ServletContainer$InternalWebComponent.initiate(ServletContainer.java:339) at com.sun.jersey.spi.container.servlet.WebComponent.load(WebComponent.java:605) at com.sun.jersey.spi.container.servlet.WebComponent.init(WebComponent.java:207) at com.sun.jersey.spi.container.servlet.ServletContainer.init(ServletContainer.java:394) at com.sun.jersey.spi.container.servlet.ServletContainer.init(ServletContainer.java:577) at javax.servlet.GenericServlet.init(GenericServlet.java:212) at org.apache.catalina.core.StandardWrapper.loadServlet(StandardWrapper.java:1213) at org.apache.catalina.core.StandardWrapper.allocate(StandardWrapper.java:827) at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:129) at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:191) at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:127) at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:103) at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:109) at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:293) at org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:861) at org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.process(Http11Protocol.java:606) at org.apache.tomcat.util.net.JIoEndpoint$Worker.run(JIoEndpoint.java:489) at java.lang.Thread.run(Unknown Source)

这里是我的web.xml文件:

<?xml version="1.0" encoding="UTF-8"?> 
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" id="WebApp_ID" version="2.5"> 
<display-name>com.labtabdb.rest</display-name> 
<welcome-file-list> 
    <welcome-file>readme.html</welcome-file> 
    <welcome-file>index.html</welcome-file> 
    <welcome-file>index.htm</welcome-file> 
    <welcome-file>index.jsp</welcome-file> 
    <welcome-file>default.html</welcome-file> 
    <welcome-file>default.htm</welcome-file> 
    <welcome-file>default.jsp</welcome-file> 
</welcome-file-list> 

<servlet> 
    <servlet-name>Jersey REST Service</servlet-name> 
    <servlet-class>com.sun.jersey.spi.container.servlet.ServletContainer</servlet-class> 
    <init-param> 
     <param-name>com.sun.jersey.config.property.packages</param-name> 
     <param-value>com.labtabdb.rest</param-value> 
    </init-param> 
    <load-on-startup>1</load-on-startup> 
</servlet> 

<servlet-mapping> 
    <servlet-name>Jersey REST Service</servlet-name> 
    <url-pattern>/nxp/*</url-pattern> 
</servlet-mapping> 

</web-app> 

下面是使用@Path注释类:

//url path for class it's methods/chemin url pour la classe et ses methodes 
@Path ("/v1/inventory") 
public class V1__inventory 
{ 


@GET //url ending in only /v1/inventory /chemin terminé par /v1/inventory 
@Produces(MediaType.APPLICATION_JSON) 
public Response errorIfNoQueryParamSpecified() throws Exception 
{ 
     return Response 
       .status(400) //bad request 
       .entity("Error: Please specify extension and parameter for this search.") 
       .build(); 
} 

/** 
* Method that returns materials filter by material name 
* @param material name 
* @return Response 
* @throws Exception 
*/ 

@Path("/{material_label}") 
@GET 
@Produces(MediaType.APPLICATION_JSON) 
public Response returnMaterial(@PathParam("material_label") String material) throws Exception 
{ 

    material = URLDecoder.decode(material, "UTF-8"); //decode URL param 
    String returnString = null; 
    JSONArray json; 

    try 
    { 

     json = LabTab_MySQLQuerys 
       .getMaterialsByName(material); 

     //if there are no results to the query 
     if(json.length() == 0) 
      throw new CustomException("No results returned"); 
     else //otherwise return results 
      returnString = json.toString(); 

    } 
    catch(CustomException e) 
    { 
     return Response 
       .status(204) 
       .entity(e.getMessage()) 
       .build(); 
    } 
    catch (Exception e) 
    { 
     e.printStackTrace(); 
     return Response 
       .status(500) //internal server error 
       .entity("Server was not able to process your request") 
       .build(); 
    } 

    return Response 
      .ok(returnString) 
      .build(); 
} 

我一直在反复搜索和阅读相同的文章3天现在nd我还没有找到解决我的错误的解决方案。

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回答

2

我要继续前进,我自己的问题作出回应,希望它可以帮助别人新的休息。

我在创建我的教程时犯了一个非常愚蠢的错误: 我的web服务的“url”例如是com.webservice.rest。当重新执行我的项目时,我决定改变我的包的名称以符合新的url:所以我的类有一个路径注释,比方说,@PATH(“/ v1/inventory”)更改为com。 webservice.inventory。

当输入新的软件包名称时,我冲过去并忘记在com.webservice中包含单词其余的其余。库存。

编写Web服务时,必须记住确保包含路径注释的每个包的前缀是Web服务的URL。

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