保存数据到表

Question

这是我的前一个问题的延伸： Auto generating dates based on a table

我得到了它完美的作品

with n as (
     select row_number() over (order by (select null)) - 1 as n 
     from master..spt_values 
    ) 
select t.*, dateadd(day, n.n, t.startDate) as thedate 
from t join 
    n 
    on dateadd(day, n.n, t.startDate) <= t.endDate; 

但是该决议，我想提出的通过将结果保存到表中来保持结果。可以持续数据吗？我试过select into语句，但它没有工作

整个语句是：收到

select into ABC 
(
    with n as (
      select row_number() over (order by (select null)) - 1 as n 
      from master..spt_values 
     ) 
    select t.*, dateadd(day, n.n, t.startDate) as thedate 
    from t join 
     n 
     on dateadd(day, n.n, t.startDate) <= t.endDate 
) 

错误是：

Msg 156, Level 15, State 1, Line 146 
Incorrect syntax near the keyword 'into'. 
Msg 319, Level 15, State 1, Line 148 
Incorrect syntax near the keyword 'with'. If this statement is a common table expression, an xmlnamespaces clause or a change tracking context clause, the previous statement must be terminated with a semicolon. 
Msg 102, Level 15, State 1, Line 168 
Incorrect syntax near ')'. 

如何将结果保存到一个表？

Answer 1

通知，其中into ABC是

;with n as (
    select row_number() over (order by (select null)) - 1 as n 
    from master..spt_values 
) 
select t.* 
    , dateadd(day, n.n, t.startDate) as thedate 
into ABC 
from t join n  
    on dateadd(day, n.n, t.startDate) <= t.endDate 

Answer 2

with n as (
      select row_number() over (order by (select null)) - 1 as n 
      from master..spt_values 
     ) 
with ABC as(
    select t.*, dateadd(day, n.n, t.startDate) as thedate 
    from t join 
     n 
     on dateadd(day, n.n, t.startDate) <= t.endDate 
) 

现在您可以在另一个查询中使用Abc。