拍摄日期'20130731'
,'20130805'
作为示例的开始和结束日期,这个查询将每天在这两个日期之间返回您需要的数量。您可以更改真实查询的参数。
;with cte as (
select d::date as d
from generate_series('20130731', '20130805', interval '1 day') as d
)
select
cte.d,
count(o.cohead_id) as cnt
from cte
left outer join cohead as o on
o.cohead_orderdate <= cte.d and
not exists (
select *
from comment as c
where
c.comment_date <= cte.d and
c.comment_text = 'Invoiced' and
c.comment_source_id = o.cohead_id
)
group by cte.d
order by cte.d
请参阅SQL FIDDLE EXAMPLE - 您可以添加/删除行并检查它是否正常工作。
希望有所帮助。
UPDATE: 如果你想获得提交日期,而不是订单日期,你不必来查询订单表都:
;with cte as (
select d::date as d
from generate_series('20130731', '20130805', interval '1 day') as d
), cte2 as (
select
c1.comment_date as submitted_date,
c2.comment_date as invoiced_date,
count(*) as cnt
from comment as c1
left outer join comment as c2 on
c2.comment_source_id = c1.comment_source_id and
c2.comment_text = 'Invoiced'
where c1.comment_text = 'Submitted'
group by c1.comment_date, c2.comment_date
)
select c1.d, sum(c2.cnt)
from cte as c1
left outer join cte2 as c2 on
c2.submitted_date <= c1.d and
(c2.invoiced_date is null or c2.invoiced_date > c1.d)
group by c1.d
order by c1.d
看到SQL FIDDLE与更新的查询
更新2由于OP说他有查询性能的问题,我试着用窗口函数编写另一个。这个想法是获取所有类型提交的日期计数减去发票类型的评论,然后获得滚动总额。
;with cte1 as (
select d::date as d
from generate_series('20130731', '20130805', interval '1 day') as d
), cte2 as (
select
greatest('20130731', c.comment_date) as comment_date,
c.comment_text, count(*) as cnt
from comment as c
where
c.comment_text in ('Invoiced', 'Submitted') and
c.comment_date <= '20130805'
group by greatest('20130731', c.comment_date), c.comment_text
), cte3 as (
select
coalesce(cs.cnt, 0) - coalesce(ci.cnt, 0) as cnt,
coalesce(cs.comment_date, ci.comment_date) as comment_date
from (select * from cte2 where comment_text = 'Submitted') as cs
full outer join (select * from cte2 where comment_text = 'Invoiced') as ci on
cs.comment_date = ci.comment_date
)
select c1.d, sum(c3.cnt) over (order by c1.d)
from cte1 as c1
left outer join cte3 as c3 on c3.comment_date = c1.d
order by c1.d
SQL FIDDLE
。 。你能提供一些样本数据和预期结果吗? –