pl/sql控制结构出错

阙使用控制结构编写一个程序来显示客户的信用额度。应该要求用户输入客户ID。根据他们的信用额度，应显示以下消息之一。如果员工的信用额度超过$ 4500，将显示最后一条消息。pl/sql控制结构出错

什么是错的这个代码，请回复

 declare   
v_emp_id employees.employee_id%type;   
    v_cust_num customers.customers#%type;  
     v_creditlimit customers.creditlimit%type;    

     begin 
     select employee_id ,customer# into v_emp_id ,  
     v_cust_num from employees natural join customers  
     where v_emp_id = '&v_emp_id';    

    if v_creditlimit < 1000 then  
    dbms_output.put_line ('credit limit less than 1000');   
     elseif v_creditlimit< 2000 then  
     dbms_output.put_line ('credit limit less than 2000');   
      elseif v_creditlimit< 3000 then  
      dbms_output.put_line ('credit limit less than 3000');   
     elseif v_creditlimit< 4000 then   
     dbms_output.put_line ('credit limit less than 4000');  
     elseif v_creditlimit< 6000 then  
     dbms_output.put_line ('credit limit less than 6000');    
     end if;  
    end;   
    /

来源

2014-02-23 user3291451

的代码是什么你得到错误？ – Incognito

不要使用'NATURAL JOIN'。让那些追随你的人（或那些试图帮助你的人）变得容易并明确指定你的加入标准。谢谢。 –

首先要开始v_creditlimit未初始化或分配给您的查询第二件事v_emp_id任何价值是你声明的变量，你利用它作为表

场尝试以下

create table customers1 (customers# int,creditlimit int,employee_id int); 

select * from customers1; 

begin 
insert into customers1 values(11,123,1); 
insert into customers1 values(12,345,2); 
commit; 
end; 
-------------------------------------------------------------------------------------- 
create table employees(employee_id int, first_name varchar2(20), last_name varchar2(20)); 

select * from employees; 

begin 
insert into employees values(1,'a','b'); 
insert into employees values(2,'c','d'); 
insert into employees values(3,'e','f'); 
commit; 
end; 
-------------------------------------------------------------------------------------- 
DECLARE 
    v_emp_id employees.employee_id%type; 
    v_cust_num customers1.customers#%type; 
    v_creditlimit customers1.creditlimit%type; 
BEGIN 

    dbms_output.put_line('Enter the employee id.'); 
    v_emp_id := &emp_id; 

    SELECT customers# INTO v_cust_num 
    FROM employees NATURAL JOIN customers1 WHERE employee_id = v_emp_id; 

    SELECT creditlimit into v_creditlimit 
    FROM employees NATURAL JOIN customers1 WHERE employee_id = v_emp_id; 

dbms_output.put_line(v_cust_num); 
dbms_output.put_line(v_creditlimit); 

    IF v_creditlimit < 1000 THEN 
    dbms_output.put_line ('credit limit less than 1000'); 
    elsif v_creditlimit BETWEEN 1001 and 2000 THEN 
    dbms_output.put_line ('credit limit BETWEEN 1001 and 2000'); 
    elsif v_creditlimit BETWEEN 2001 and 3000 THEN 
    dbms_output.put_line ('credit limit BETWEEN 2001 and 3000'); 
    elsif v_creditlimit BETWEEN 3001 and 4000 THEN 
    dbms_output.put_line ('credit limit BETWEEN 3001 and 4000'); 
    elsif v_creditlimit BETWEEN 5001 and 6000 THEN 
    dbms_output.put_line ('credit limit BETWEEN 5001 and 6000'); 
    END IF; 

END;

来源

2014-02-23 13:55:06

pl/sql控制结构出错

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