SQL Server 2008中逗号分隔字段中的组计数值

Question

我有一个users表，其列product。

我想指望有多少产品是在我的表

Users表

+----------+ 
| Products | 
+----------+ 
| A  | 
| B  | 
| A,c  | 
| C,B,A | 
| D  | 
+----------+ 

即计数A为：3人，占B为2，计数C为：2 ，计数d是：1

Answer 1

请尝试：

SELECT Products, COUNT(Products) 
FROM(
    SELECT 
     Split.a.value('.', 'VARCHAR(100)') AS Products 
    FROM 
    (
     SELECT 
      CAST ('<M>' + REPLACE(Products, ',', '</M><M>') + '</M>' AS XML) AS CVS 
     from YourTable 
    ) AS A CROSS APPLY CVS.nodes ('/M') AS Split(a) 
)x GROUP BY Products 

Answer 2

使用递归查询 - STE递归分割的2个柱体P - l - 包含没有逗号和r入门 - 中Products尾，之后，使GROUP BY通过l柱：

WITH expandProd as(
    SELECT 
     CASE 
      WHEN charindex(',', Products) < 1 THEN Products 
      ELSE LEFT(Products, charindex(',', Products)-1) 
     END as l, -- the column without comma 
     CASE 
      WHEN charindex(',', Products) < 1 THEN NULL 
      ELSE RIGHT(Products, LEN(Products) - charindex(',', Products)) 
     END as r -- the column with tail 
    FROM prods 
    UNION ALL --recursive query that enters again to itself 
    SELECT 
     CASE 
      WHEN charindex(',', r) < 1 THEN r 
      ELSE LEFT(r, charindex(',', r)-1) 
     END as l, 
     CASE 
      WHEN charindex(',', r) < 1 THEN NULL 
      ELSE RIGHT(r, LEN(r) - charindex(',', r)) 
     END as r 
    FROM expandProd 
WHERE r is not null --small optimization 
) 
SELECT l, COUNT(l) 
    FROM expandProd 
    GROUP BY l