CTE不评估所有的选择标准正确

Question

早安，

我已经写了下面的存储过程，搜索具有指定为指定的程序和标志一个或多个收费代码记录那些为ProcGrouper = 1和必要性识别那些没有对比费用的账户（标记为ContrastGrouper = 0）。

当我运行sproc和审计帐户时，我看到很多对比费用。因此，CTE似乎没有正确评估所有标准。我该如何补救？

with cteGrouper 
as 
(
SELECT [ENCOUNTER NUMBER], 
[DATE OF SERVICE], [FEEDER KEY], 
[CHGDTL CPT4 CODE], CASE 
WHen [FEEDER KEY] IN ('76803520121','76803520120','76803520112','76803520111', 
'76803520110','76803520109','76803520108','76803520034','76803520030','76803520027', 
'76803520025','76803520017','76803520015','76803520014','76803510073','76803510072', 
'76803510064','76803510012','76803510011','76803510008','76803510003','76803510002', 
'76803510068','76803520031','76803520028','76803520107','76803520022','76803520020', 
'76803520106','76803510009','76803510070','76803510069','76803510067','76803510065', 
'76803510074','76704027052','76606123003','76606123001','76606120012','76606111003', 
'76606102043','76606100011','76606102040','76606121006','76606121009','76606123002', 
'76606102053','76606102042') then 1 else 0 
end as ProcGrouper, 
Case when [Feeder Key] in ('76806360076', '76806360077','76806360089','76806360090', 
'76306360509','76306360513','76306360514','75706362105','76806366053','75706366054', 
'75706366055','76606360099') then 1 else 0 
end as ContrastGrouper 
FROM ENCOUNTERCHGDTL 
where ([Date of Service] between @StartDate and @EndDate) 
), 
cteFilterAccounts 
as 
(
Select [Encounter Number], 
[Date of Service], [Feeder Key], 
[Chgdtl CPT4 Code], ProcGrouper, ContrastGrouper 
from cteGrouper 
where ProcGrouper=1 
and ContrastGrouper=1 
) 

Select [Encounter Number], 
[Feeder Key], 
[Date of Service], 
[Chgdtl CPT4 Code] 
,[ADMITDATE - CCYYMMDD], [DISCHARGEDATE - CCYYMMDD], 
[DISCHARGEDISPOSITION], ProcGrouper, ContrastGrouper 
from cteGrouper 
join Encounter on [Encounter Number]=[EncounterNumber] 
and AdmitSubService <>'SIG' 
and HSP#='1' 
and ActualTotalCharge>0 
where ProcGrouper=1 
and ContrastGrouper=0 
and [Encounter Number] not in 
(Select [Encounter Number] from cteFilterAccounts) 

Order by [ENCOUNTER NUMBER] 
END 

Answer 1

我想你应该重新定义你的cteFilterAccounts CTE。问题是，您现在的CTE代码会返回一组个人行cteGroup同时具有ProcGrouper=1和ContrastGrouper=1。基于对cteGroup代码，可以永远不可能的，因为行可以有一个[Feeder Key]属于不超过一个两组，所以它的要么ProcGrouper=1或ContrastGrouper=1，但不能同时使用。因此，CTE不会返回任何结果。

尽管在逻辑上，您似乎在搜索同时在全球范围内设置了两个属性的行，即在期间内的。一个可能的解决方案是使用连接，像这样：

cteFilterAccounts AS (
    SELECT g1.[Encounter Number] 
    FROM (
    SELECT DISTINCT [Encounter Number], 
    FROM cteGrouper 
    WHERE ProcGrouper=1 
) g1 
    INNER JOIN (
    SELECT DISTINCT [Encounter Number], 
    FROM cteGrouper 
    WHERE ContrastGrouper=1 
) g2 ON g1.[Encounter Number] = g2.[Encounter Number] 
) 

该查询从在期限内发现，有类似的列表，其中[Feeder Key]属于另一组一组加入与[Feeder Key]所有[Encounter Number]值。匹配值会给出结果集。

另外，您可以使用INTERSECT：

cteFilterAccounts AS (
    SELECT [Encounter Number], 
    FROM cteGrouper 
    WHERE ProcGrouper=1 
    INTERSECT 
    SELECT [Encounter Number], 
    FROM cteGrouper 
    WHERE ContrastGrouper=1 
) 

基本上，它使用相同的逻辑连接。

您也可以尝试一种完全不同的方式，分组，像这样：

cteFilterAccounts AS (
    SELECT [Encounter Number] 
    FROM cteGrouper 
    GROUP BY [Encounter Number] 
    HAVING MAX(ProcGrouper) = 1 
    AND MAX(ContrastGrouper) = 1 
) 

这里你选择那些既Grouper属性最大（聚合）值等于1

独立的帐户