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如何重复此程序,但在第二次或第三次向他们显示时保留用户输入等。程序询问他们想要坐的位置,然后显示器向他们显示X代替他们在哪里说过。我希望X在下一次请求输入之前留下来,直到用户决定通过选择“2”决定退出程序。如何存储用户输入以便继续使用?
import java.util.Scanner;
import java.util.Arrays;
class AirplaneSeating {
static Scanner inNum = new Scanner(System.in);
static Scanner inStr = new Scanner(System.in);
static void option() {
String[][] seatingChart = new String[10][4];
int rows = 10;
int columns = 4;
seatingChart = new String[rows][columns];
for(int i = 0; i < rows; i++) {
for(int j = 0; j < columns; j++) {
seatingChart[i][j] = "" + ((char)('A' + i)) + ((char)('1' + j));
}
}
for(int i = 0; i < rows ; i++) {
for(int j = 0; j < columns ; j++) {
System.out.print(seatingChart[i][j] + " ");
}
System.out.println("");
}
System.out.println("What seat would you like to reserve? ");
String str = inStr.nextLine();
System.out.println("You chose: " + str);
for(int i = 0; i < rows ; i++) {
for(int j = 0; j < columns ; j++) {
if(seatingChart[i][j].equals(str)) {
System.out.print("X" + " ");
} else {
System.out.print(seatingChart[i][j] + " ");
}
}
System.out.println("");
}
}
public static void main(String[] args) {
int choice;
do {
System.out.println("Choose from one of the following options:");
System.out.println("\tl. Choose a seat to reserve: ");
System.out.println("\t2. Quit");
System.out.print("Enter 1 or 2: ");
choice = inNum.nextInt();
switch(choice) {
case 1:
option();
break;
case 2:
System.out.println("\nGoodbye!");
break;
default:
System.out.println(choice + " is not an option. Please choose 1, 2, 3, 4, or 5.");
}
}while(choice !=2);
}
}
你必须从某处加载它,例如。文件,文本文件,服务器。因此,创建一个带有2个值的.txt文件非常简单...如果它是一个类,并且您想要将它加载到您应该查看Serializable –