1
curl -F [email protected]/path/to/index.html -u [email protected] -F 'data={"title":"API V1 App","package":"com.alunny.apiv1","version":"0.1.0","create_method":"file"}' https://build.phonegap.com/api/v1/apps
我想要使用一个使用HttpClient库的java程序实现相同的功能。使用java的cURL命令
DefaultHttpClient client = new DefaultHttpClient();
HttpHost targetHost = new HttpHost("build.phonegap.com", 443, "https");
client.getCredentialsProvider().setCredentials(
new AuthScope(targetHost.getHostName(), targetHost.getPort(),AuthScope.ANY_REALM),
new UsernamePasswordCredentials("[email protected]", "abc123"));
String authToken = "?auth_token=abcdefgh";
HttpPost httpPost = new HttpPost("https://build.phonegap.com/api/v1/apps" + authToken);
String jsonString = "{\"title\":\"API V1 App\",\"create_method\":\"file\"}";
MultipartEntity multipartEntity = new MultipartEntity();
multipartEntity.addPart(new FormBodyPart("data", new StringBody(jsonString)));
multipartEntity.addPart("file", new FileBody(new File("C:/Users/Desktop/app.zip")));
/*StringEntity entity = new StringEntity(jsonString, "UTF-8"); */
httpPost.setEntity(multipartEntity);
System.out.println("executing request " + httpPost.getRequestLine());
HttpResponse httpResponse = client.execute(httpPost);
HttpEntity entity = httpResponse.getEntity();
System.out.println(httpResponse.getStatusLine());
if(entity != null){
System.out.println(EntityUtils.toString(entity));
}
在上面的代码中，我只能设置StringEntity或FileEntity但不同时，我认为这是什么是需要得到curl命令的功能。
与StringEntity和FileEntity努力之后，我试着用MultipartEntity，但没有运气.. 能否请您为我提供更多的细节，如果可能的例子..
在此先感谢。