添加ROW_NUMBER影响汇总

Question

行的顺序我有以下几点：

CREATE TABLE food_delivery 
(
    foodtype varchar(50) NOT NULL, 
    foodname varchar(50) NOT NULL, 
    numitems int NOT NULL 
) 
go 

INSERT INTO food_delivery 
VALUES 
('vegetable', 'carrot', 30), 
('vegetable', 'carrot', 50), 
('vegetable', 'potato', 40), 
('vegetable', 'potato', 60), 
('fruit', 'apple', 50), 
('fruit', 'apple', 70), 
('fruit', 'banana', 60), 
('fruit', 'banana', 80) 
GO 

现在，当我运行此查询：

SELECT foodtype, foodname, SUM(numitems) 
FROM food_delivery 
GROUP BY foodtype, foodname WITH ROLLUP 

我得到这个：

foodtype  foodname  
------------ ------------ ----------- 
fruit  apple  120 
fruit  banana  140 
fruit  NULL   260 
vegetable carrot  80 
vegetable potato  100 
vegetable NULL   180 
NULL   NULL   440 

我我很高兴与此订购，但我也想添加每种食物类型的项目的排名，所以我有这样的事情：

foodtype  foodname     
------------ ------------ ----------- -------------------- 
fruit  apple  120   1 
fruit  banana  140   2 
fruit  NULL   260   3 
vegetable carrot  80   1 
vegetable potato  100   2 
vegetable NULL   180   3 
NULL   NULL   440   1 

这个想法是，我想识别排名为1的行，并对它们进行不同处理。

所以这是我使用查询：

SELECT foodtype, foodname, SUM(numitems), 
     ROW_NUMBER() OVER (PARTITION BY foodtype ORDER BY foodname, SUM(numitems)) 
FROM food_delivery 
GROUP BY foodtype, foodname WITH ROLLUP 

不幸的是，在添加ROW_NUMBER（）完全抛出我的结果集不正常的顺序，我得到这个：

foodtype  foodname     
------------ ------------ ----------- -------------------- 
NULL   NULL   440   1 
fruit  NULL   260   1 
fruit  apple  120   2 
fruit  banana  140   3 
vegetable NULL   180   1 
vegetable carrot  80   2 
vegetable potato  100   3 

即摘要是在每个组的顶部，而不是在底部。

任何人都可以告诉我如何在每个组的底部获得我的摘要，同时仍然有我的排名？

谢谢。

---

编辑：那么乔恩·赛格尔的回答给我我想要的，但我还是不明白，为什么其他的解决方案不起作用。

借此：

SELECT CASE WHEN foodtype IS NULL THEN 0 ELSE 1 END, 
     foodtype, 
     CASE WHEN foodname IS NULL THEN 0 ELSE 1 END, 
     foodname, 
     SUM(numitems), 
     ROW_NUMBER() OVER (PARTITION BY foodtype 

ORDER BY CASE WHEN foodtype IS NULL THEN 0 ELSE 1 END, 
      foodtype, 
      CASE WHEN foodname IS NULL THEN 0 ELSE 1 END, 
      foodname DESC) RankVal 

FROM food_delivery 
GROUP BY foodtype, 
      foodname WITH ROLLUP 

ORDER BY CASE WHEN foodtype IS NULL THEN 0 ELSE 1 END, 
      foodtype, 
      CASE WHEN foodname IS NULL THEN 0 ELSE 1 END, 
      foodname DESC 

这几乎是相同的Jon的溶液，不同之处在于我有顺序为降序，我移调和在THEN 0 ELSE 1。在我看来，这应该给我相同的结果（即NULLS将为0，并且由于它们正在被分类为DESC，它们应该出现在该集合的底部）。然而，返回的结果集是这样的：

  foodtype     foodname     RankVal 
----------- ------------ ----------- ------------ ----------- -------------------- 
0   NULL   0   NULL   440   1 
1   fruit  0   NULL   260   1 
1   fruit  1   banana  140   2 
1   fruit  1   apple  120   3 
1   vegetable 0   NULL   180   1 
1   vegetable 1   potato  100   2 
1   vegetable 1   carrot  80   3 

正如你可以看到，从CASE语句的结果不是按降序排列。

Answer 1

SELECT 
    foodtype, 
    foodname, 
    NumItems, 
    ROW_NUMBER() OVER 
    (
     PARTITION BY foodtype 
     ORDER BY 
      (CASE WHEN foodtype IS NULL THEN 1 ELSE 0 END), 
      foodtype, 
      (CASE WHEN foodname IS NULL THEN 1 ELSE 0 END), 
      foodname 
    ) AS Rank 
    FROM 
    (
     SELECT 
      foodtype, 
      foodname, 
      SUM(numitems) AS NumItems 
      FROM food_delivery 
      GROUP BY foodtype, foodname WITH ROLLUP 
    ) a 
    ORDER BY 
     (CASE WHEN foodtype IS NULL THEN 1 ELSE 0 END), 
     foodtype, 
     (CASE WHEN foodname IS NULL THEN 1 ELSE 0 END), 
     foodname 

Answer 2

尝试明确指定ORDER BY。

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SELECT foodtype, 
     foodname, 
     SUM(numitems), 
     ROW_NUMBER() OVER (PARTITION BY foodtype ORDER BY foodname, SUM(numitems)) RankVal 
FROM @food_delivery 
GROUP BY foodtype, 
      foodname WITH ROLLUP 

ORDER BY CASE WHEN foodtype IS NULL THEN 1 ELSE 0 END, 
      foodtype, 
      CASE WHEN foodname IS NULL THEN 1 ELSE 0 END, 
      foodname, 
      RankVal