2015-09-26 48 views
0

即时编写代码,根据您的年龄和性别,它会显示,如果你可以参加军队,但由于某种原因,在阅读第一个声明后,它已经跳转到结果没有评估第二个条件。这里是代码:If Else语句跳过第二个条件

package exercicios1; 
import java.util.Scanner; 

public class Idade 
{ 
private int Age; 
private String Gender; 

public int getAge() 
{ 
    return Age; 
} 

public void setIdade(int age) 
{ 
    Age = age; 
} 

public String getGender() 
{ 
    return Gender; 
} 

public void setGender(String G) 
{ 
    Gender = G; 
} 

public void ageVerification() 
{ 
    Scanner input = new Scanner(System.in); 
    System.out.print("Please enter your age: "); 
    Age = input.nextInt(); 
    System.out.print("Please enter your gender(M/F) :"); 
    Gender = input.nextLine(); 

    if(18 <= Age & Age <= 27 & Gender.equals("m")) 
    { 
     System.out.printf("You are viable to be enlisted"); 
    } 
    else 
    { 
     System.out.printf("You are not viable to be enlisted"); 
    } 
} 
+2

见http://stackoverflow.com/questions/13102045/skipping-nextline-after-using-next-nextint-or-other-nextfoo-methods –

回答

1

添加此行后年龄= input.nextInt();

input.nextLine();