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我想要创建一个代码,它将显示一个窗口的按钮,点击后会创建另一个窗口的一些字段(如QLabel,QLineEdit,QSpinBox等)。不过,我不知道如何创建一个弹出窗口...点击按钮弹出窗口
这里是我的代码:
#!/usr/bin/env python
# -*- coding: utf-8 -*-
import sys # Needed for PySide
from PySide.QtCore import *
from PySide.QtGui import *
class Form(QDialog):
def __init__(self, parent=None):
super(Form, self).__init__(parent)
# Create widgets
self.label1 = QLabel("Label1")
self.button_open = QPushButton("Open popup")
self.button = QPushButton("Go!")
self.qbtn = QPushButton('Quit')
# Create layout and add widgets
layout = QVBoxLayout()
layout.addWidget(self.label1)
layout.addWidget(self.button_open)
# Buttons layout
hbox_buttons = QHBoxLayout()
hbox_buttons.addStretch(1)
hbox_buttons.addWidget(self.button)
hbox_buttons.addWidget(self.qbtn)
# Main layout
layout.addStretch(1)
layout.addWidget(self.button_open)
layout.addLayout(hbox_buttons)
self.setLayout(layout)
# Add buttons slots
self.button_open.clicked.connect(self.popup)
self.button.clicked.connect(self.function_runner)
self.qbtn.clicked.connect(QCoreApplication.instance().quit)
def popup (self, parent=__init__):
new_win = # I wonder what should be here
if __name__ == '__main__':
# Create the Qt Application
app = QApplication(sys.argv)
# Create and show the form
form = Form()
form.show()
# Run the main Qt loop
sys.exit(app.exec_())
我知道你在四月要求,可能已经转移,但我一直在寻找的正是这种答案的说法。看看pyside示例代码中的qdialog示例:http://qt.gitorious.org/pyside/pyside-examples查看示例/对话框中的代码,我认为您在寻找的是standarddialogs.py文件。 – James 2012-09-06 02:26:39