如果你想要一个真正动态的网格,那么你可以在代码中构建网格。这有点棘手,但并非不可能。这是一个独立的例子,你可以看看。
<%@ Page Language="C#" AutoEventWireup="true"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<script runat="server">
class MyItemTemplate : System.Web.UI.ITemplate
{
public void InstantiateIn(System.Web.UI.Control container)
{
Label label = new Label();
label.ID = "MyLabel";
container.Controls.Add(label);
}
}
protected void Page_Load(object sender, EventArgs e)
{
GridView gv;
if (!this.IsPostBack)
{
gv = new GridView();
gv.AutoGenerateColumns = false;
gv.ID = "MyGrid";
var column = new TemplateField();
column.HeaderText = "My Item";
column.ItemTemplate = new MyItemTemplate();
gv.Columns.Add(column);
MyDiv.Controls.Add(gv);
gv.RowDataBound += new GridViewRowEventHandler(gv_RowDataBound);
}
var dataSource = new string[] { "a", "b", "c" };
gv = this.Page.FindControl("MyGrid") as GridView;
gv.DataSource = dataSource;
gv.DataBind();
}
void gv_RowDataBound(object sender, GridViewRowEventArgs e)
{
var label = e.Row.FindControl("MyLabel") as Label;
if (label != null)
label.Text = ((string)e.Row.DataItem).ToUpper();
}
</script>
<html xmlns="http://www.w3.org/1999/xhtml">
<head runat="server">
<title></title>
</head>
<body>
<form id="form1" runat="server">
<div id="MyDiv" runat="server">
</div>
</form>
</body>
</html>
感谢您的回复。两个问题1)这是应该动态创建的列。实际的GridView应该以标准方式修复和创建。 2)我需要在单元格内显示图像 – user935811
1)本示例动态创建列2)您创建的列可以有一个占位符,您可以在其中添加图像。 –
谢谢埃里克,我是asp.net的新手....你有#2的例子吗? – user935811