我在更新Silverlight的依赖项属性时遇到问题。我正在设置一个属性并通知它在我的父类中已更改。自定义控件通过依赖属性侦听此属性的更改,但它从不打它(调用更改回调)。我一直在玩这个游戏,唯一一次能够击中它的是如果我设置了一个默认值,但它永远不会达到新的值。我正在设置断点并查看这些值的变化,甚至将一个带有NotificationModel.Type对象的文本块放入它中,并且它正常更改。请帮忙!Silverlight的依赖属性没有更新/更改
Main.xaml
<views:NotificationView x:Name="NotificationView" Grid.Column="0" Grid.Row="1" Grid.ColumnSpan="2" Notification="{Binding Path=DataContext.Notification, ElementName=LayoutRoot, Mode=TwoWay}"></views:NotificationView>
MainViewModel.cs
void part_NotificationChanged(object sender, NotificationChangedEventArgs e)
{
Notification = new NotificationModel()
{
Notifications = e.Notification.Notifications,
Type = e.Notification.Type
};
}
private NotificationModel _notification;
public NotificationModel Notification
{
get
{
return _notification;
}
set
{
_notification = value;
this.OnPropertyChanged("Notification");
}
}
NotificationView.xaml.cs
public partial class NotificationView : UserControl
{
public NotificationView()
{
InitializeComponent();
}
public NotificationModel Notification
{
get
{
return (NotificationModel)GetValue(NotificationProperty);
}
set
{
SetValue(NotificationProperty, value);
}
}
public static readonly DependencyProperty NotificationProperty =
DependencyProperty.Register("Notification", typeof(NotificationModel), typeof(NotificationView), new PropertyMetadata(new PropertyChangedCallback(OnNotificationChanged)));
private static void OnNotificationChanged(DependencyObject d, DependencyPropertyChangedEventArgs e)
{
NotificationView view = d as NotificationView;
if (view != null)
{
NotificationModel notification = e.NewValue as NotificationModel;
if (notification != null)
{
switch (notification.Type)
{
case NotificationType.Success:
view.LayoutRoot.Children.Add(new SuccessView() { Message = notification.Notifications.FirstOrDefault() });
break;
case NotificationType.Error:
view.LayoutRoot.Children.Add(new ErrorsView() { Errors = notification.Notifications });
break;
case NotificationType.Caution:
break;
default:
view.LayoutRoot.Children.Clear();
break;
}
}
}
}
}
相信我我也这样做了,它只是留下了代码,我尝试使用,而不是刚才提到的代码,但它的工作原理虽然如此。是的,它必须以某种方式默默地失败,我不能指出如何或在哪里。 – 2010-10-21 21:56:09