调用C＃中IDispatch COM接口的成员＃

Question

我想从实现IDispatch接口的COM对象中调用GetIdsOfNames函数。我写了下面的代码，但是它失败了，并且DISP_E_UNKNOWNNAME。这是做这件事的正确方法吗？

Object so = Activator.CreateInstance(Type.GetTypeFromProgID("ProgID"));    
Object[] args = new Object[5]; 
string[] rgsNames = new string[1]; 
rgsNames[0] = "PrintNormal"; 
uint LOCALE_SYSTEM_DEFAULT = 0x0800; 
uint lcid = LOCALE_SYSTEM_DEFAULT; 
int cNames = 1; 
int[] rgDispId = new int[1]; 
args[0] = IntPtr.Zero; 
args[1] = rgsNames; 
args[2] = cNames; 
args[3] = lcid; 
args[4] = rgDispId;    
Object result = so.GetType().InvokeMember("GetIDsOfNames", BindingFlags.InvokeMethod, null, so, args); 

感谢，

理查德

Answer 1

，你不行，因为InvokeMember内部使用的GetIDsOfNames，而这一次只检查实际的方法，而不是在IDispatch的第6。换句话说，不能使用IDispatch的方法Invoke调用GetIDsOfNames。这就是COM的工作原理。

Answer 2

是的，不起作用，RCW不公开IDispatch方法。您必须明确获取IDispatch接口引用。这工作得很好：

using System; 
using System.Runtime.InteropServices; 
using System.Runtime.InteropServices.ComTypes; 

class Program { 
    static void Main() { 
     Object so = Activator.CreateInstance(Type.GetTypeFromProgID("SAPI.SpVoice")); 
     string[] rgsNames = new string[1]; 
     int[] rgDispId = new int[1]; 
     rgsNames[0] = "Speak"; 
     IDispatch disp = (IDispatch)so; 
     Guid dummy = Guid.Empty; 
     disp.GetIDsOfNames(ref dummy, rgsNames, 1, 0x800, rgDispId); 
     Console.WriteLine(rgDispId[0]); 
    } 

    [ComImport, InterfaceType(ComInterfaceType.InterfaceIsIUnknown), Guid("00020400-0000-0000-C000-000000000046")] 
    private interface IDispatch { 
     int GetTypeInfoCount(); 
     [return: MarshalAs(UnmanagedType.Interface)] 
     ITypeInfo GetTypeInfo([In, MarshalAs(UnmanagedType.U4)] int iTInfo, [In, MarshalAs(UnmanagedType.U4)] int lcid); 
     void GetIDsOfNames([In] ref Guid riid, [In, MarshalAs(UnmanagedType.LPArray)] string[] rgszNames, [In, MarshalAs(UnmanagedType.U4)] int cNames, [In, MarshalAs(UnmanagedType.U4)] int lcid, [Out, MarshalAs(UnmanagedType.LPArray)] int[] rgDispId); 
    } 
}