Python前十名单

Question

list = ('Bob', 11, 333, 453.3, 'Ted', 15, 999, 345.5, 'Jeff', 22, 122, 434.7) 

嗨，我试图从上述信息建立前10名单。

第一个值：目标， 第二个值：助攻 第三个值：时间出场

我希望能够找到在这种情况下，总 的最高目标，我想给用户得到的结果是：

1）杰夫：22 2）泰德：15 3）鲍勃：11

Answer 1

您应该使用这里的字典：

>>> lis = ('Bob', 11, 333, 453.3, 'Ted', 15, 999, 345.5, 'Jeff', 22, 122, 434.7) 
>>> dic = { lis[i]: list(lis[i+1:i+4]) for i in xrange(0,len(lis),4)} 
>>> dic 
{'Bob': [11, 333, 453.3], 
'Ted': [15, 999, 345.5], 
'Jeff': [22, 122, 434.7]} 

>>> sorted(dic,key = dic.get,reverse = True) 
['Jeff', 'Ted', 'Bob'] 

# To get keys as well as values use dict.items() 
>>> for k,v in sorted(dic.items(), key =lambda x:x[1] , reverse = True): 
    print k,v[0] 
...  
Jeff 22 
Ted 15 
Bob 11 

Answer 2

>>> from operator import itemgetter 
>>> data = ('Bob', 11, 333, 453.3, 'Ted', 15, 999, 345.5, 'Jeff', 22, 122, 434.7) 
>>> for x in sorted(zip(*[iter(data)]*4), key=itemgetter(1), reverse=True): 
     print x[0], x[1] 


Jeff 22 
Ted 15 
Bob 11