假设你也有(或创建)一个名为表与一个记录每个10分钟开始时间, 如何@Times ...
Select T.Start,
(Select Count(*) From testTab
Where Start Between T.Start
And DateAdd(minute, 10, T.Start)) New,
(Select Count(*) From testTab
Where Start < DateAdd(minute, 10, T.Start)
And EndDt > DateAdd(minute, 10, T.Start)) ActiveAtEnd,
(Select Max(Cnt) From
(Select Count(Distinct T.Which) Cnt
From (Select Distinct Start
From testTab
Where Start Between T.Start
And DateAdd(minute, 10, T.Start)
Union Select T.Start
Union Select DateAdd(minute, 10, T.Start)) Z
Left Join testTab T
On Z.Start Between T.Start And T.EndDt
Group By Z.Start) ZZ) MaxActive,
(Select Min(Cnt) From
(Select Count(Distinct T.Which) Cnt
From (Select Distinct Start
From testTab
Where Start Between T.Start
And DateAdd(minute, 10, T.Start)
Union Select T.Start
Union Select DateAdd(minute, 10, T.Start)) Z
Left Join testTab T
On Z.Start Between T.Start And T.EndDt
Group By Z.Start) ZZ) MinActive
From @Times T
我创建了SQL Server作为一个表变量此表,使用
Declare @Times Table (Start datetime Primary key Not Null)
Declare @Start DateTime
Set @Start = '1 Nov 2008 10:00'
While @Start < '1 Nov 2008 11:00' begin
Insert @Times(Start) values(@Start)
Set @Start = DateAdd(minute, 10, @Start)
End
若y ou正在使用另一种产品,请使用临时表代替...但这种方法确实需要一个表,每个十分钟“期间”有一个记录作为运行的一个钩子...
用以下数据查询生成输出如下:
start endDt Which
----------------------- ----------------------- -----
2008-11-01 10:01:00.000 2008-11-01 10:12:00.000 A
2008-11-01 10:03:00.000 2008-11-01 10:06:00.000 B
2008-11-01 10:05:00.000 2008-11-01 10:25:00.000 C
2008-11-01 10:14:00.000 2008-11-01 10:42:00.000 D
2008-11-01 10:32:00.000 2008-11-01 10:36:00.000 E
2008-11-01 10:22:00.000 2008-11-01 10:51:00.000 F
2008-11-01 10:22:00.000 2008-11-01 10:23:00.000 G
Start New ActiveAtEnd MaxActive MinActive
----------------------- ----------- ----------- ----------- -----------
2008-11-01 10:00:00.000 3 2 3 0
2008-11-01 10:10:00.000 1 2 2 2
2008-11-01 10:20:00.000 2 2 4 2
2008-11-01 10:30:00.000 1 2 3 2
2008-11-01 10:40:00.000 0 1 2 1
2008-11-01 10:50:00.000 0 0 1 0
警告:空值由集合或其他SET操作消除。
什么样的列是开始和结束?他们是日期还是varchar2? – 2008-11-19 12:42:32