2015-12-09 34 views
-2

我被分配了一个大学项目的错误处理任务,我无法让它工作。我需要使用Try catch捕获SQL错误,并将用户重定向到显示错误的新页面error.php。我知道这不是处理错误的最佳方式,但这正是教授想要的。PHP错误处理 - 重定向

下面是从页的一个我试图捉对错误的例子:

<?php 
    $orderid = $_REQUEST['orderid']; 
    connectDB(); // database connections are defined in connect_to_DB.php 

    try{ 
     $strSql2 = "SELECT `order_date`, `status_id`, `emp_id`,`cust_id` FROM `salesorder` WHERE `order_id`='" .$orderid. "'" ; 

     $result = @mysqli_query($db, $strSql2) // or die("SQL error: " . mysqli_error()); 

     if($row = mysqli_fetch_array($result)){ 
      $orderDate = $row["order_date"]; 
      $orderStatus=$row["status_id"]; 
      $empid = $row["emp_id"]; 
      $custid=$row["cust_id"]; 

      if(!$result){ 
       throw new Exception(mysqli_error($db)); 
      } 

      mysqli_free_result($result); // Always release the recordset memory resources 
      mysqli_close($db); // Always close the database connection 

      connectDB(); 
      $sqlcount = "SELECT COUNT(order_id) AS numrows FROM orderitem WHERE order_id=".$_REQUEST['orderid']; 
      $resultcount = @mysqli_query($db,$sqlcount) // or die ("SQL error: ".mysqli_error()); 

      if($rowcount= mysqli_fetch_array($resultcount)){ 
       $orderamount = $rowcount['numrows']; 
       if(!$resultcount){ 
        throw new Exception(mysqli_error($db)); 
       } 

       mysqli_free_result($resultcount); 
       mysqli_close($db); 
      } 
     } 
    } catch (Exception $e){ 
     // redirect to a php error page 
     header("Location: error.php?msg=" . $e->getMessage() . "&line=" . $e->getLine()); 
    } 

这是错误页面代码,error.php

<? 
    print "Error message: " . $_GET["msg"]; 
    if(isset($_GET["line"])){ 
     print " - line number: " . $_GET["line"]; 
    } 

对不起误删除这篇文章的结尾......现在有一条错误,在第66行if($row = mysqli)的if语句中,我无法弄清楚。在我开始添加错误处理之前,一切正常。

在此先感谢您的帮助。

+0

继续你的功课,有什么问题吗? (使用urlencode的味精) – KiwiJuicer

+2

只要你用'@'来抑制输出,你就无法捕捉东西 –

+0

@JayBlanchard我的印象是@只是压制给定函数调用的消息,而不是错误本身 – colyerfs

回答

1

你缺少分号:

$result = @mysqli_query($db, $strSql2); 
+0

谢谢,清除了如果声明错误 – colyerfs

+0

是的,这就是所有错误的代码! – RiggsFolly

0

1)更改if($row = mysqli_fetch_array($result)){while($row = mysqli_fetch_array($result)){

2)前while($row = mysqli_fetch_array($result)){因为if(!$result){是假的,那么为什么会得while循环将if(!$result){throw new Exception(mysqli_error($db));}

3)不要进行多重连接。

<?php 
$orderid = $_REQUEST['orderid']; 
connectDB(); // database connections are defined in connect_to_DB.php 

try{ 
    $strSql2 = "SELECT `order_date`, `status_id`, `emp_id`,`cust_id` FROM `salesorder` WHERE `order_id`='" .$orderid. "'" ; 

    $result = @mysqli_query($db, $strSql2) // or die("SQL error: " . mysqli_error()); 

    if(!$result){ 
     throw new Exception(mysqli_error($db)); 
    } 

    while($row = mysqli_fetch_array($result)){ 
      . 
      . 
      // Remove this close and open connection. 
      //mysqli_close($db); // Always close the database connection 
      //connectDB(); 

    } 
} catch (Exception $e) { 
    header("Location: error.php?msg=" . $e->getMessage() . "&line=" . $e->getLine()); 
} 
+0

是的,多数民众赞成在该代码错了! – RiggsFolly

+0

谢谢,清除if语句错误 – colyerfs

+0

@colyerfs:检查一次。 –

0

有一个在你的代码只是这么多的错误,我将只提供这个作为一个更好的起点,供您

<?php 
$orderid = $_REQUEST['orderid']; 

// connect only once per script 
// useful comment here would be 

// connectDB() set the connection handle onto $db in the global scope 
// not good practice but at least now we know 
connectDB(); 

try{ 
    $sql = "SELECT `order_date`, `status_id`, `emp_id`,`cust_id` 
      FROM `salesorder` 
      WHERE `order_id`='$orderid'" ; 

    $result = mysqli_query($db, $sql); 
    // test statuses when you receive them not sometime later 
    // after attempting to use a potentially useless mysqli::result object 

    if(!$result){ 
     throw new Exception(mysqli_error($db)); 
    } 


    $row = mysqli_fetch_array($result); 

    $orderDate = $row["order_date"]; 
    $orderStatus = $row["status_id"]; 
    $empid  = $row["emp_id"]; 
    $custid  = $row["cust_id"]; 


    $sql = "SELECT COUNT(order_id) AS numrows 
      FROM orderitem 
      WHERE order_id={$_REQUEST['orderid']}"; 

    $resultcount = mysqli_query($db,$sqlcount); 

    // again test status now not later 
    if(!$resultcount){ 
     throw new Exception(mysqli_error($db)); 
    } 

    // only one result row so no loop necessary 
    $row = mysqli_fetch_array($resultcount)){ 

    $orderamount = $row['numrows']; 

} catch (Exception $e){ 
    // redirect to a php error page 
    header("Location: error.php?msg=" . $e->getMessage() . "&line=" . $e->getLine()); 
}