您好在XML属性的XML序列化中存在一些问题,下面是从XSD生成的类文件的一些细节。如何在XML序列化中添加XML属性C#
/// <remarks/>
[System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "4.0.30319.17929")]
[System.SerializableAttribute()]
[System.Diagnostics.DebuggerStepThroughAttribute()]
[System.ComponentModel.DesignerCategoryAttribute("code")]
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType=true, Namespace="http://tempuri.org/UpdatePolicy.xsd")]
public partial class policyClasses {
private policyClassesClass[] classField;
/// <remarks/>
[System.Xml.Serialization.XmlElementAttribute("class")]
public policyClassesClass[] @class {
get {
return this.classField;
}
set {
this.classField = value;
}
}
}
/// <remarks/>
[System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "4.0.30319.17929")]
[System.SerializableAttribute()]
[System.Diagnostics.DebuggerStepThroughAttribute()]
[System.ComponentModel.DesignerCategoryAttribute("code")]
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType=true, Namespace="http://tempuri.org/UpdatePolicy.xsd")]
public partial class policyClassesClass {
private string company_idField;
private string deductable_rateField;
private string max_limitField;
private string class_nameField;
private string class_numberField;
private policyClassesClassCchi_class_number cchi_class_numberField;
private policyClassesClassAction_type action_typeField;
private bool action_typeFieldSpecified;
/// <remarks/>
public string company_id {
get {
return this.company_idField;
}
set {
this.company_idField = value;
}
}
/// <remarks/>
[System.Xml.Serialization.XmlElementAttribute(DataType="positiveInteger")]
public string deductable_rate {
get {
return this.deductable_rateField;
}
set {
this.deductable_rateField = value;
}
}
/// <remarks/>
[System.Xml.Serialization.XmlElementAttribute(DataType="positiveInteger")]
public string max_limit {
get {
return this.max_limitField;
}
set {
this.max_limitField = value;
}
}
/// <remarks/>
public string class_name {
get {
return this.class_nameField;
}
set {
this.class_nameField = value;
}
}
/// <remarks/>
public string class_number {
get {
return this.class_numberField;
}
set {
this.class_numberField = value;
}
}
/// <remarks/>
public policyClassesClassCchi_class_number cchi_class_number {
get {
return this.cchi_class_numberField;
}
set {
this.cchi_class_numberField = value;
}
}
/// <remarks/>
[System.Xml.Serialization.XmlAttributeAttribute()]
public policyClassesClassAction_type action_type {
get {
return this.action_typeField;
}
set {
this.action_typeField = value;
}
}
/// <remarks/>
[System.Xml.Serialization.XmlIgnoreAttribute()]
public bool action_typeSpecified {
get {
return this.action_typeFieldSpecified;
}
set {
this.action_typeFieldSpecified = value;
}
}
}
/// <remarks/>
[System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "4.0.30319.17929")]
[System.SerializableAttribute()]
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType=true, Namespace="http://tempuri.org/UpdatePolicy.xsd")]
public enum policyClassesClassCchi_class_number {
/// <remarks/>
[System.Xml.Serialization.XmlEnumAttribute("1")]
Item1,
/// <remarks/>
[System.Xml.Serialization.XmlEnumAttribute("2")]
Item2,
/// <remarks/>
[System.Xml.Serialization.XmlEnumAttribute("3")]
Item3,
/// <remarks/>
[System.Xml.Serialization.XmlEnumAttribute("4")]
Item4,
}
/// <remarks/>
[System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "4.0.30319.17929")]
[System.SerializableAttribute()]
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType=true, Namespace="http://tempuri.org/UpdatePolicy.xsd")]
public enum policyClassesClassAction_type {
/// <remarks/>
[System.Xml.Serialization.XmlEnumAttribute("10")]
Item10,
/// <remarks/>
[System.Xml.Serialization.XmlEnumAttribute("1")]
Item1,
我设法基于这个类的序列化XML,但没有任何想法将XML属性添加到生成的XML,我认为如下得到一个输出。
<classes>
<class action_type="10">
<company_id>999</company_id>
<deductable_rate>20</deductable_rate>
<max_limit>800</max_limit>
<class_name>Class A</class_name>
<class_number>1</class_number>
<cchi_class_number>2</cchi_class_number>
</class>
如何将属性从/// <remarks/> [System.Xml.Serialization.XmlAttributeAttribute()] public policyClassesClassAction_type action_type { get { return this.action_typeField; } set { this.action_typeField = value; } }
<class action_type = "10">
请别人帮助我在此来管理我的最后期限,还告诉我,如果有什么不明确的宝贵回应 Joe
如果你没有得到“ACTION_TYPE”属性值,那么它可能是空 –