我有以下的代码,从表中根据自己的日志中的细节得到了用户的数据PHP和MySQL查询,以获取名称
//==========================================
// CONNECT TO THE LOCAL DATABASE
//==========================================
$user_name = "xxxx";
$pass_word = "xxxxx";
$database = "xxxx";
$server = "xxxxxx";
$db_handle = mysql_connect($server, $user_name, $pass_word);
$db_found = mysql_select_db($database, $db_handle);
if ($db_found) {
$SQL = "SELECT * FROM students WHERE L1 = '$uname' AND L2 = '" .md5 ($_POST['password'])."'";
$result = mysql_query($SQL);
$num_rows = mysql_num_rows($result);
//====================================================
// CHECK TO SEE IF THE $result VARIABLE IS TRUE
//====================================================
if ($result) {
if ($num_rows > 0) {
$color="1";
$result = mysql_query("SELECT * FROM entry, students WHERE entry.studentName = students.studentName AND students.L1='$uname' ") or die(mysql_error());
echo "<p>Welcome "; echo $row[studentName];
echo "<p>You records as of ";
echo date('l jS \of F Y h:i:s A');
echo "<table border='1' cellpadding='2' cellspacing='0'>";
echo "<tr> <th>Date</th><th>Student Name</th> <th>Tutor name</th> <th>Procedure name</th> <th>Grade</th><th>Student Reflection</th><th>Tutor Comments</th><th>Professionalism</th> <th>Communication</th> <th>Alert</th> <th>Dispute</th> </tr>";
// keeps getting the next row until there are no more to get
while($row = mysql_fetch_array($result)) {
if($color==1){
echo "<tr bgcolor=#DDD ><td>".$row['date']."</td><td>".$row['studentName']."</td><td>".$row['tutorName']."</td><td>".$row['procedureName']."</td><td>".$row['grade']."</td><td>".$row['studentReflection']."</td><td>".$row['tutorComments']."</td><td>".$row['professionalism']."</td><td>".$row['communication']."</td><td>".$row['alert']."</td><td>".$row['dispute']."</td></tr>";
// Set $color==2, for switching to other color
$color="2";
}
// When $color not equal 1, use this table row color
else {
echo "<tr bgcolor='#CCC'><td>".$row['date']."</td><td>".$row['studentName']."</td><td>".$row['tutorName']."</td><td>".$row['procedureName']."</td><td>".$row['grade']."</td><td>".$row['studentReflection']."</td><td>".$row['tutorComments']."</td><td>".$row['professionalism']."</td><td>".$row['communication']."</td><td>".$row['alert']."</td><td>".$row['dispute']."</td></tr>";
// Set $color back to 1
$color="1";
}
}
echo '</table>';
}
我想这样做是回声或打印出用户名在桌子上方,但我很难这样做。唯一需要的就是将它添加到while循环中,然后将其打印出来的次数与用户记录的次数相同。
你能帮忙吗?
我看到一个错误代码:你声明$ user_name和在您的SQL查询你使用$ UNAME –
这是没有问题的。我可以很好地连接到数据库并获取用户记录,但在生成表之前,我想回显用户全名,该用户全名保存在学生表中。$ uname用于我使用的html日志类型表单让学生登录 – user1132612
不是说这会回答你的问题,但如果你使用PHP5,你不应该使用mysql_命令,因为它们已被弃用。您应该切换到使用mysqli或PDO。 – Codeguy007