有人能告诉我为什么下面的代码只能得到除查询以外的查询中的所有图片吗?查询没有得到所有mysql_fetch_assocs的
$userquery = mysql_query("SELECT * FROM acceptedfriends WHERE profilename='$profilename' ORDER BY RAND() LIMIT 4");
while ($userrun = mysql_fetch_assoc($userquery))
{
$users = $userrun['username'];
$imagequery = mysql_query("SELECT * FROM users2 WHERE username='$users'");
while ($imagefetch = mysql_fetch_assoc($imagequery))
{
$location = $imagefetch['imagelocation'];
$image = "<img src='$location' width='60' height='40'>";
if ($profilename==$username)
{
echo '<div id="hovercolor2" style="width:294px; float:left;"><table><tr> <td>'.$image.'</td><td><div style="margin-bottom:5px;"><a href="http://www.pearlsquirrel.com/'.$users.'" target="_blank">'.$users.'</a></div><div><a href="http://www.pearlsquirrel.com/conversation.php/'.$users.'" style="text-decoration:underline;" target="_blank"><div style="font-size:.7em";>Click to enter a conversation.</div></a></div></td></tr></table></div><div id="hrdiv3" style="float:left; width:298px;"></div>';
}
else
{
echo '<div id="hovercolor2" style="width:294px; float:left;"><table><tr><td>'.$image.'</td><td><a href="http://www.pearlsquirrel.com/'.$users.'" target="_blank">'.$users.'</a></td></tr></table></div><div id="hrdiv3" style="float:left; width:298px;"></div>';
}
}
}
这
$image = "<img src='$location' width='60' height='40'>";
没有查询获得最后一张图像。我花了大约一小时试图解决这个问题,不知道。任何帮助,将不胜感激。
具有相同的错误
$userquery = mysql_query("SELECT * FROM acceptedfriends WHERE profilename='$profilename' ORDER BY id DESC LIMIT 6");
while ($userrun = mysql_fetch_assoc($userquery))
{
$users = $userrun['username'];
$location = $userrun['imagelocation'];
$image = "<img src='$location' style='width:60px; height:40px;'>";
if ($profilename==$username)
{
echo '<div id="hovercolor2" style="width:294px; float:left;"><table><tr><td>'.$image.'</td><td><div style="margin-bottom:5px;"><a href="http://www.pearlsquirrel.com/'.$users.'" target="_blank">'.$users.'</a></div><div><a href="http://www.pearlsquirrel.com/conversation.php/'.$pageusers.'" style="text-decoration:underline;" target="_blank"><div style="font-size:.7em";>Click to enter a conversation.</div></a></div></td></tr></table></div><div id="hrdiv3" style="float:left; width:298px;"></div>';
}
else
{
echo '<div id="hovercolor2" style="width:294px; float:left;"><table><tr><td>'.$image.'</td><td><a href="http://www.pearlsquirrel.com/'.$users.'" target="_blank">'.$users.'</a></td></tr></table></div><div id="hrdiv3" style="float:left; width:298px;"></div>';
}
}
你没有得到最后的图像吗?使用mysql_num_rows()来获得返回的行数,从那里我们可以进一步调查。 – Chibuzo 2012-01-13 02:29:21
所以你只能得到3张图片?并通过','图像=“”;'真的应该''图像=“”;':) – davogotland 2012-01-13 02:37:34