STUFF和Oracle11g查询中的XML路径

Question

下面是一个示例数据：从此表中，如果stringvalue包含或等于ID，则基于满足的条件获取代码，并使用stringvalue检查ID。如果至少有1个满足条件，则查询将连接代码的任何值并将其置于新代码之下。

Scenario 1 
    ID   CODE  VALUE    Newcode 
    4   42        44,45 
    4   43        44,45 
    4   44   2,4,6    44,45 
    4   45   2,4,6    44,45 

Scenario 2 

ID  CODE   VALUE    Newcode 
4   42      44 
4   43      44 
4   44   4   44 
4   45   3   44 

Answer 1

只需使用list_agg：

select sub.mainid, list_agg(cast(sub_code as nvarchar(100)), ',') 
from ENPTREEATTRS SUB 
WHERE SUB.CODE in ('42','43','44','45') and 
     SUB.STRINGVALUE LIKE '%'||cast(id as nvarchar(100))||'%' 
group by sub.mainid 

顺便说一句，你不应该在SQL Server中使用convert(nvarchar, id)。您应该始终提供一个长度，例如convert(nvarchar(100), id)。

Answer 2

根据您的更新，你应该能够使用子查询来获取列表数据，然后加入该回你的表：

SELECT DISTINCT 
    ID, 
    CODE, 
    ATTRSTRINGVALUE, 
    SUB.Newcode 
FROM Table1 A 
INNER JOIN tabel2 b 
    ON a.MainID = b.mainID 
LEFT JOIN 
(
    SELECT SUB.MainID, 
    list_agg(cast(SUB.CODE as nvarchar2(50)), ',') as Newcode 
    FROM ENPTREEATTRS SUB 
    WHERE SUB.CODE in ('42','43','44','45') 
    AND SUB.STRINGVALUE LIKE '%'||cast(ID as nvarchar2(50))||'%' 
    GROUP BY SUB.MainID 
) SUB 
    ON SUB.MainID = A.MainID 

编辑＃1，您张贴您可以在新的查询后，用途：

SELECT DISTINCT 
    ID, 
    CODE, 
    ATTRSTRINGVALUE, 
    SUB.Newcode 
FROM ENPBATREE A 
LEFT OUTER JOIN enptreeattrs B on A.MainID = B.MainID 
LEFT OUTER JOIN ENPTREEATTRS B1 on B.MainID = B1.MainID 
LEFT OUTER JOIN ENPTREEATTRS B2 on B1.MainID = B2.MainID 
LEFT OUTER JOIN ENPENTRYACCESSUSERSROLES D on B2.MainID = D.MainID 
LEFT OUTER JOIN ENPENTRYACCESSLIST F on D.USERNAME = F.USERNAME 
LEFT JOIN 
(
    SELECT SUB.MainID, 
    list_agg(cast(SUB.CODE as nvarchar2(50)), ',') as Newcode 
    FROM ENPTREEATTRS SUB 
    WHERE SUB.CODE in ('42','43','44','45') 
    AND SUB.STRINGVALUE LIKE '%'||cast(ID as nvarchar2(50))||'%' 
    GROUP BY SUB.MainID 
) SUB 
    ON SUB.MainID = A.MainID 

您可能能够在没有子查询执行此：

SELECT 
    A.TREEENTRYID, 
    F.accessid, 
    b1.ATTRID, 
    b1.attrstringvalue, 
    list_agg(cast(SUB.ATTRID as nvarchar2(50)), ',') as Newcode 
FROM ENPBATREE A 
LEFT OUTER JOIN enptreeattrs B on A.TREEENTRYID = B.TREEENTRYID 
LEFT OUTER JOIN ENPTREEATTRS B1 on B.TREEENTRYID = B1.TREEENTRYID 
LEFT OUTER JOIN ENPTREEATTRS B2 on B1.TREEENTRYID = B2.TREEENTRYID 
LEFT OUTER JOIN ENPENTRYACCESSUSERSROLES D on B2.TREEENTRYID = D.TREEENTRYID 
LEFT OUTER JOIN ENPENTRYACCESSLIST F on D.USERNAME = F.USERNAME 
LEFT JOIN enptreeattrs SUB 
    ON SUB.MainID = A.MainID 
WHERE SUB.ATTRID in ('42','43','44','45') 
    AND SUB.ATTRSTRINGVALUE LIKE '%'||cast(F.ACCESSID as nvarchar2(50))||'%' 
GROUP BY A.TREEENTRYID, F.ACCESSID, 
    b1.ATTRID, b1.attrstringvalue; 

SELECT 
    ID, 
    CODE, 
    ATTRSTRINGVALUE, 
    list_agg(cast(SUB.CODE as nvarchar2(50)), ',') as Newcode 
FROM ENPBATREE A 
LEFT OUTER JOIN enptreeattrs B on A.MainID = B.MainID 
LEFT OUTER JOIN ENPTREEATTRS B1 on B.MainID = B1.MainID 
LEFT OUTER JOIN ENPTREEATTRS B2 on B1.MainID = B2.MainID 
LEFT OUTER JOIN ENPENTRYACCESSUSERSROLES D on B2.MainID = D.MainID 
LEFT OUTER JOIN ENPENTRYACCESSLIST F on D.USERNAME = F.USERNAME 
LEFT JOIN ENPTREEATTRS SUB 
    ON SUB.MainID = A.MainID 
WHERE SUB.CODE in ('42','43','44','45') 
    AND SUB.STRINGVALUE LIKE '%'||cast(ID as nvarchar2(50))||'%' 
GROUP BY ID, CODE, ATTRSTRINGVALUE