基于外观的枢轴数据

Question

我期望为部门的每个服务编号获取标志。对于我写了下面的旋转功能，但它不是按我的预期输出

DECLARE @MyTab TABLE 
(
     Service_Number VARCHAR(20), 
     Department VARCHAR(20) 
) 

INSERT INTO @MyTab VALUES ('12A','ABC'), ('12A','XYZ'), ('12B','ABC'), ('12C','PQR') 

SELECT * FROM @MyTab 

SELECT 
             [ABC],[xyz],[pqr] 

       FROM @MyTab 
       PIVOT(    MAX(Service_Number)  
       FOR Service_Number IN ([ABC],[xyz],[pqr])) AS P 

输出：

预期输出：

Service_Number ABC XYZ PQR 
12A   1 1 0 
12B   1 0 0 
12C   0 1 1 

Answer 1

你需要改变主要部分如下：

SELECT * from 
    (Select Service_Number, Department FROM @MyTab) a 
PIVOT(Count(Department) FOR Department IN ([ABC],[xyz],[pqr])) AS P 

Service_Number没有[ABC]，[XYZ] ...

输出如下：

+----------------+-----+-----+-----+ 
| Service_Number | ABC | xyz | pqr | 
+----------------+-----+-----+-----+ 
| 12A   | 1 | 1 | 0 | 
| 12B   | 1 | 0 | 0 | 
| 12C   | 0 | 0 | 1 | 
+----------------+-----+-----+-----+