从定界符分隔的oracle db中提取clob的值

Question

我有一个存储xml的Oracle DB CLOB字段。我需要使用DistributionNbr标记检索所有xml中的所有值我已经对以下查询使用了相同的参数，并为ref提供了一个示例xml。

select extract(xmltype(column_name),'//*/xmlpath/text()').getStringval() as g 
from table; 

<xml> 
<ShipConfirm> 
<ShipmentID>000000196</ShipmentID> 
</ShipConfirm> 
<ShipConfirm> 
<ShipmentID>000000197</ShipmentID> 
</ShipConfirm> 
<ShipConfirm> 
<ShipmentID>000000198</ShipmentID> 
</ShipConfirm> 
</xml> 

现在我得到的值作为一个字符串：000000196000000197000000198

我需要在下一行逗号分隔值或值。 000000196,000000197,000000198

OR

000000196 
000000197 
000000198 

Answer 1

请避免不必要的“//”，运营商...和列图案隐含相对于行模式

SQL> with MY_TABLE as 
    2 (
    3 select 1 as PRIMARY_KEY, 
    4   XMLTYPE(
    5 '<xml> 
    6 <ShipConfirm> 
    7  <ShipmentID>000000196</ShipmentID> 
    8 </ShipConfirm> 
    9 <ShipConfirm> 
10  <ShipmentID>000000197</ShipmentID> 
11 </ShipConfirm> 
12 <ShipConfirm> 
13  <ShipmentID>000000198</ShipmentID> 
14  </ShipConfirm> 
15 </xml>') as XML_DOC 
16  from DUAL 
17 ) 
18 SELECT LISTAGG(x.ShipmentID, ',') WITHIN GROUP (ORDER BY idx) AS ShipmentIDs 
19 FROM MY_TABLE t, 
20   XMLTABLE(
21   '/xml/ShipConfirm' 
22   PASSING XML_DOC 
23   COLUMNS 
24    idx FOR ORDINALITY, 
25    ShipmentID CHAR(9) PATH 'ShipmentID' 
26  ) x 
27 GROUP BY t.primary_key 
28/

SHIPMENTIDS 
-------------------------------------------------------------------------------- 
000000196,000000197,000000198 

SQL> 
SQL> 

Answer 2

使用XMLTABLE：

SELECT x.ShipmentID 
FROM your_table t 
     CROSS JOIN 
     XMLTABLE(
     '//xml/ShipConfirm' 
      PASSING XMLTYPE(t.column_name) 
      COLUMNS ShipmentID CHAR(9) PATH './ShipmentID' 
     ) x; 

这将在行其返回。

如果你想把它当作逗号分隔值那么你可以使用：

SELECT LISTAGG(x.ShipmentID, ',') WITHIN GROUP (ORDER BY idx) 
     AS ShipmentIDs 
FROM your_table t 
     CROSS JOIN 
     XMLTABLE(
     '//xml/ShipConfirm' 
      PASSING XMLTYPE(t.column_name) 
      COLUMNS ShipmentID CHAR(9) PATH './ShipmentID', 
        idx FOR ORDINALITY 
     ) x 
GROUP BY t.primary_key;