如何使用用户输入在Java中填充二维数组？

Question

我想通过使用用户输入的字符串填充Java中的二维数组。我已经得到了字符串，我已经想出了如何创建数组。我只是无法弄清楚如何将值存入数组。如果你想知道，是的，我必须使用一个数组。以下是我迄今为止：

private static int[][] parseTwoDimension(String strInput) 
     { 
      int rows = 0; //number of rows in the string 

      for (int i = 0; i < strInput.length(); i++) 
      { 
       if (strInput.charAt(i) == '!') //the ! is an indicator of a new row 
       { 
        rows++; 
       } 
      } 

      int[][] arr = new int[rows][]; //create an array with an unknown number of columns 
      int elementCounter = 0; //keep track of number of elements 
      int arrayIndexCounter = 0; //keep track of array index 

      for (int i = 0; i < strInput.length(); i++) 
      { 
       if (strInput.charAt(i) != '!') //while not the end of the row 
       { 
        elementCounter++; //increase the element count by one 
       } 
       else //reached the end of the row 
       { 
        arr[arrayIndexCounter] = new int[elementCounter]; //create a new column at the specified row 
        elementCounter = 0; //reset the element counter for the next row 
        arrayIndexCounter++; //increase the array index by one 
       } 
      } 
     /* 
     This is where I need the help to populate the array 
     */ 
     char c; //each character in the string 
     int stringIndex = -1; //keep track of the index in the string 
     int num; //the number to add to the array 
     for (int i = 0; i < arr.length; i++) 
     { 
      for (int j = 0; j < arr[i].length; j++) 
      { 
       stringIndex++; //increment string index for next element 
       c = strInput.charAt(stringIndex); //the character at stringIndex 
       if (c == '!') //if it is the end of the row, do nothing 
       { 

       } 
       else //if it is not the end of the row... 
       { 
        String s = Character.toString(c); //convert character to String 
        num = Integer.parseInt(s); //convert String to Integer 
        arr[i][j] = num; //add Integer to array 
       } 
      } 
     } 
     return arr; //return a two dimensional array the user defined 
    } 

任何帮助是极大的赞赏:)

Answer 1

我已经编辑你的代码，并张贴在下面。这是怎么解决的一个大致轮廓：“！”

1. 使用string.split（“！”）由分隔符的字符串分隔。这将返回数组

2. 然后，使用string.split（ “”）来分隔字符串为单个字符

代码贴在下面：

private static int[][] parseTwoDimension(String strInput) 
{ 
    String[] rows = strInput.split("!");  
    int[][] arr = new int[rows.length()][]; 

    for(int i = 0; i < rows.length; i++) 
    { 
     String[] elements = rows[i].split(""); 
     int[] intElements = new int[elements.length]; 

     for(int j = 0; j < elements.length; j++) 
     { 
      intElements[j] = Integer.parseInt(elements[j]); 
     } 
     arr[i] = intElements; 
    } 
} 

让我知道如果这个作品。在将字符串解析为数组时，string.split（）函数非常有用