0
我的咖啡代码建立WebSocket连接时它不存在返回错误:的WebSocket建立防弹连接
socket = new WebSocket('ws://localhost:8080')
#=> Firefox can't establish a connection to the server at ws://localhost:8080/.
#=> socket = new WebSocket('ws://localhost:8080');
它的WebSocket的正常行为,但我想WebSockets的工作是这样的:
# pseudocode
if websocket.establish_connection()
# do thing #1
else
do thing no.2
我想约try
... catch
但我认为它很脏。有其他解决方法吗?
有一些'readyState'财产,也许这有助于http://stackoverflow.com/questions/11809267/how-do-i -know-IF-连接是活与 - 的WebSockets –