-3
在Java中,我有一个这样的数组:如何统计Java中列表对象中的重复值?
String[] city = {"texas", "ny", "sydney", "ny", "paris", "texas", "ny"};
我想排序/它们与数组...喜欢 -
texas = 2
ny = 3
sydney = 1
paris = 1
在Java中,我有一个这样的数组:如何统计Java中列表对象中的重复值?
String[] city = {"texas", "ny", "sydney", "ny", "paris", "texas", "ny"};
我想排序/它们与数组...喜欢 -
texas = 2
ny = 3
sydney = 1
paris = 1
使用Collections.frequency()
方法。
import java.util.Arrays;
import java.util.Collections;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
public class Test{
public static void main(String[] args) {
String[] city = {"texas", "ny", "sydney", "ny", "paris", "texas", "ny"};
List<String> asList = Arrays.asList(city);
Map<String, Integer> map= new HashMap<String, Integer>();
for(String s: city){
map.put(s,Collections.frequency(asList,s));
}
System.out.println(map);
}
}
+1对于'Collections#frequency(java.util.Collection,Object)' – tmwanik
你有没有尝试过任何东西? (提问更好的问题的有用链接:[问],[FAQ]) – Doorknob
尝试'Map'。 –
adatapost