获得共同的元组元素

Question

我怎么能拒绝这样的：

(("and", "dog"), ("a", "dog")) 

进入这个：

("and", "dog", "a") 

这意味着越来越常见的元素"dog"只有一次。

Answer 1

>>> tuple(set(("and", "dog")) | set(("a", "dog"))) 
('and', 'a', 'dog') 

或者一般：

import operator 
tuple(reduce(operator.__or__, map(set, mytuples))) 

Answer 2

你可以将它转换为set。

diff = (set(("a","dog")) - set(("and","dog"))) 
result = list(("and","dog")) + list((diff)) 
print(result) #['and', 'dog', 'a'] 

Answer 3

如果顺序并不重要：

>>> tuple(set.union(*map(set, tuples))) 
('and', 'a', 'dog') 

如果为了做事情：

>>> seen = set() 
>>> tuple(elem for tupl in tuples for elem in tupl 
      if elem not in seen and not seen.add(elem)) 
('and', 'dog', 'a')