在C＃中序列化类。嵌套的XML

Question

我在下面格式

<objects> 
    <items> 
     <item ="delete"> 
      <searchfields> 
      <searchfield name="itemname" value="itemValue" /> 
      </searchfields> 
     </item> 
    </items> 
</objects> 

因此，我已生成使用XSD.EXE由上述XML转换为XSD的CS文件来生成XML。

xsd.exe -c -l:c# -n:XmlSerializationDeleteObject DeleteObject.xsd 

生成的CS文件包含4个类。

我的问题是我必须用上面提到的格式使用生成的类来构建XML。我能够逐个序列化类文件，每次都会退回一个标签，但我无法按照上面提到的方式构建它。

请帮

Regardas， jebli

Answer 1

我想这应该千方百计想让你想要的。我不得不说，我没有'使用XSD创建我的类 - 我从头开始创建它们。

using System; 
using System.Collections.Generic; 
using System.Linq; 
using System.Text; 
using System.Xml.Serialization; 
using System.Collections; 

namespace TestLibrary 
{ 
    [Serializable] 
    [XmlRoot("Objects")] 
    public class ObjectTest : ICollection 
    { 
     [XmlArray("Items")] 
     public Items[] items; 

     #region "Required for implementing ICollection" 
     //Default Accessor 
     public Items this[int index] 
     { 
      get { return (Items)items[index]; } 
     } 

     public void CopyTo(Array array, int index) 
     { 
      items.CopyTo(array, index); 
     } 

     public int Count 
     { 
      get { return items.Length; } 
     } 

     public bool IsSynchronized 
     { 
      get { return false; } 
     } 

     public object SyncRoot 
     { 
      get { return this; } 
     } 



     public IEnumerator GetEnumerator() 
     { 
      return items.GetEnumerator(); 
     } 

     public void Add(Items newItems) 
     { 
      if (this.items == null) 
      { 
       this.items = new Items[1]; 
      } 
      else 
      { 
       Array.Resize(ref this.items, this.items.Length + 1); 
      } 
      this.items[this.items.GetUpperBound(0)] = newItems; 

     } 
     #endregion 
    } 

    [Serializable] 
    public class Items 
    { 
     [XmlElement("Item")] 
     public Item item; 



    } 
    [Serializable] 
    public class Item 
    { 
     [XmlAttribute("itemType")] 
     public string itemType; 


     [XmlArray("SearchField")] 
     public SearchFields[] searchfields; 
    } 

    [Serializable] 
    public class SearchFields 
    { 

     [XmlAttribute("name")] 
     public string searchName; 

     [XmlAttribute("value")] 
     public string searchValue; 

    } 


} 

然后这将创建实际的XML文件 - 这与您的示例几乎相同。唯一的区别是，我认为你必须Item元素的属性来保存"delete"

private void button1_Click(object sender, EventArgs e) 
     { 
      //Create the Serialize object to save the class to an XML file 
      XmlSerializer serializer = new XmlSerializer(typeof(ObjectTest)); 
      FileStream fs = new FileStream(@"C:\Objects.xml", FileMode.Create); 

      try 
      { 


       //Create new instances of each class to store the data 
       ObjectTest testing = new ObjectTest(); 
       Items newItems = new Items(); 
       Item newItem = new Item(); 
       SearchFields newSearch = new SearchFields(); 

       //Assign SearchField data 
       newSearch.searchName = "itemName"; 
       newSearch.searchValue = "itemValue"; 

       //Assign the item type 
       newItem.itemType = "delete"; 

       //Create a new array of SearchField objects 
       SearchFields[] testSearch = { newSearch }; 

       //Add the SearchField array to the Item class 
       newItem.searchfields = testSearch; 

       //Add the single Item class to the Items class 
       newItems.item = newItem; 

       //Create a new array of Items objects 
       Items[] testItems = { newItems }; 

       //Add the Items array to the ObjectTest class 
       testing.items = testItems; 

       //Serialize the object 
       serializer.Serialize(fs, testing); 


      } 
      catch (Exception ex) 
      { 
       MessageBox.Show("Error: " + ex.ToString()); 
      } 
      finally 
      { 
       //close the objects 
       fs.Close(); 
       serializer = null; 

      } 



     } 

让我知道你上车。我希望这是你正在寻找的。

感谢

巴里