如何将int转换为24位字符串？

Question

读我使用：

def UI24(t): 
    result = 0 
    for i in xrange(3): 
     result = (result << 8); 
     byte = unpack('>b',t[i-1]) 
     result += byte; 
    return result 

和写？

Answer 1

这没有测试！

def UI24back(value): 
    result = "" 
    for i in xrange(3): 
     result = pack('>b', value &255) + result 
     value >>= 8 
    return result 

Answer 2

简单只是垫他们当作多头

>>> from struct import pack, unpack 
>>> def unpack24(s): 
...  return unpack(">L","\0"+s)[0] 
... 
>>> def pack24(i): 
...  return pack(">L",i)[1:] 
...