即使在提供第一个输入后，如何添加程序继续执行的功能？

Question

我正在写一个Hailstone序列程序，并且我想为程序添加能力，即使在第一个输入和输出已经打印之后，它仍然可以继续计算。基本上，不是重新运行程序，而是继续提供输入。

public class HailStoneSequence { 
    static Scanner MyScanner = new Scanner(System.in); 
    public static void main(String[] args) { 
    System.out.println("Enter a number to generate the Hailstone Sequence for that number. "); 
    int num = MyScanner.nextInt(); //Taking input from user 
    while (num>1) 
    { 
     if (num%2 == 0) 
     { 
     num /= 2; 
     System.out.print(num+" "); 
     } 
     else 
     { 
     num = (num*3)+ 1; 
     System.out.print(num+" "); 
     } 
    } 
    } 
} 

Answer 1

刚好围绕代码块while循环来检查，如果输入例如为0，在这种情况下，0意味着执行结束。

import java.util.Scanner; 
public class HailStoneSequence { 
    static Scanner MyScanner = new Scanner(System.in); 
    public static void main(String[] args) { 
    int num = 1; 
    while(num != 0) { 
     System.out.println("Enter a number to generate the Hailstone Sequence for that number. "); 
     num = MyScanner.nextInt(); //Taking input from user 
     while (num>1) 
     { 
      if (num%2 == 0) 
      { 
      num /= 2; 
      System.out.print(num+" "); 
      } 
      else 
      { 
      num = (num*3)+ 1; 
      System.out.print(num+" "); 
      } 
     } 
    } 
    } 

} 

Answer 2

您可以使用while循环，让您的程序运行，像这样：

System.out.println("Enter a number to generate the Hailstone Sequence for that number:(0 to quit) "); 
int num = MyScanner.nextInt(); //Taking input from user 
while(num != 0){ 
    //logic 
    System.out.println("Enter a number to generate the Hailstone Sequence for that number:(0 to quit) "); 
    num = MyScanner.nextInt(); //Taking input from user 
} 

然后在你的逻辑结束时再次采取输入。该计划将继续运行，直到用户输入一个密钥（在这种情况下，0）

Answer 3

你可以做这样的事情：

String input = ""; 
do { 
    // Your code here 
    System.out.println("Continue?"); 
    input = MyScanner.next(); 
} while (!input.equals("exit");