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我在将this C# code转换为WebAPI 2 VB.Net项目时遇到了一些困难。将PushStreamContent C#代码转换为VB.Net时出错WebAPI 2
这里是原来的C#代码
[HttpGet]
public HttpResponseMessage FromImages() {
var imageStream = new ImageStream();
Func<Stream, HttpContent, TransportContext, Task> func = imageStream.WriteToStream;
var response = Request.CreateResponse();
response.Content = new PushStreamContent(func);
response.Content.Headers.Remove("Content-Type");
response.Content.Headers.TryAddWithoutValidation("Content-Type", "multipart/x-mixed-replace;boundary=" + imageStream.Boundary);
return response;
}
internal class ImageStream {
public object Boundary { get; private set; } = "HintDesk";
public async Task WriteToStream(Stream outputStream, HttpContent content, TransportContext context) {
byte[] newLine = Encoding.UTF8.GetBytes("\r\n");
foreach (var file in Directory.GetFiles(@"TestData\Images", "*.jpg")) {
var fileInfo = new FileInfo(file);
var header = $"--{Boundary}\r\nContent-Type: image/jpeg\r\nContent-Length: {fileInfo.Length}\r\n\r\n";
var headerData = Encoding.UTF8.GetBytes(header);
await outputStream.WriteAsync(headerData, 0, headerData.Length);
await fileInfo.OpenRead().CopyToAsync(outputStream);
await outputStream.WriteAsync(newLine, 0, newLine.Length);
await Task.Delay(1000/30);
}
}
}
下面是VB.Net翻译
<HttpGet> _
Public Function FromImages() As HttpResponseMessage
Dim imageStream = New ImageStream()
Dim func As Func(Of Stream, HttpContent, TransportContext, Task) = imageStream.WriteToStream
Dim response = Request.CreateResponse()
response.Content = New PushStreamContent(func)
response.Content.Headers.Remove("Content-Type")
response.Content.Headers.TryAddWithoutValidation("Content-Type", "multipart/x-mixed-replace;boundary=" + imageStream.Boundary)
Return response
End Function
Friend Class ImageStream
Public Function WriteToStream(outputStream As Stream, content As HttpContent, context As TransportContext) As Task
Dim newLine As Byte() = Encoding.UTF8.GetBytes(vbCr & vbLf)
For Each file As var In Directory.GetFiles("TestData\Images", "*.jpg")
Dim fileInfo = New FileInfo(file)
Dim header = "--{Boundary}" & vbCr & vbLf & "Content-Type: image/jpeg" & vbCr & vbLf & "Content-Length: {fileInfo.Length}" & vbCr & vbLf & vbCr & vbLf
Dim headerData = Encoding.UTF8.GetBytes(header)
Await outputStream.WriteAsync(headerData, 0, headerData.Length)
Await fileInfo.OpenRead().CopyToAsync(outputStream)
Await outputStream.WriteAsync(newLine, 0, newLine.Length)
Await Task.Delay(1000/30)
Next
End Function
End Class
我看到两个问题:
在这条线是一个“参数没有为'Public Function WriteToStream ...'的参数'context'指定'
昏暗FUNC作为Func键(中流,HttpContent,TransportContext,任务)= imageStream.WriteToStream
的重载决策失败,因为没有可访问的 '新' 可以用这些参数
响应被称为。内容=新PushStreamContent(FUNC)
我想,我没有正确翻译这一点,但我很难找到在VB.Net任何实例为了我想要完成的事情。有人能告诉我我做错了什么吗?
的伎俩,和漂亮的风风火火的边界属性 – user1532208