GridView SelectedIndexChanged - 返回被点击的项目

我有一个ASP.NET DataGrid，在最后返回三个可点击的列。运行SelectedIndexChanged时，如何返回被点击的项目的值？GridView SelectedIndexChanged - 返回被点击的项目

感谢

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Private Sub DG_SelectedIndexChanged(sender As Object, e As EventArgs) 
    Try 
     Dim DG As GridView = CType(sender, GridView) 
     Dim vID As Integer = DG.SelectedRow.Cells(0).Text 
     'Need to determine which item was clicked here 
    Catch ex As Exception 

    End Try 
End Sub

来源

2014-11-21 gchq

我有点惊讶，你上面的代码不起作用...几乎我会做。 – Zack 2014-11-21 21:21:59

这是另一种方式：http://msdn.microsoft.com/en-us/library/system.web.ui.webcontrols.gridview.selectedrow(v=vs.110).aspx?cs-save -lang = 1＆cs-lang = vb＃code-snippet-2 – jyrkim 2014-11-21 21:24:18

Zack - 代码工作并返回被选中的ROW，但我需要知道点击了三列中的哪个链接 – gchq 2014-11-21 21:29:08

最后，我发现的唯一办法是一个onclick事件添加到LinkButton的

AG_Link.Text = "View Agenda" 
AG_Link.Attributes.Add("onclick", "returnDocumentType('Agenda');")

添加一些JavaScript来更新一个隐藏的文本框，然后拿起结果

Private Sub DG_SelectedIndexChanged(sender As Object, e As EventArgs) 
    Try 
     Dim DG As GridView = CType(sender, GridView) 
     Dim vID As Integer = DG.SelectedRow.Cells(0).Text 
     Dim DocumentType As String = DocumentTypeTB.Text 

    Catch ex As Exception 

    End Try 

End Sub

一个很长的路，但它的工作原理:-)

来源

2014-11-21 23:50:42 gchq

GridView SelectedIndexChanged - 返回被点击的项目

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