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首先,这里是我的数据库是什么样子:结合2个复杂的MySQL查询到一个
当前 - 表
ID - Unique identifier for device (Int)
Location -Unique identifier for name of area (VarChar)
Status - The current status of the device (VarChar)
Time - DateTime of when the last connection was made to the device (DateTime)
历史 - 表
CID (Sorta unused, just as an AI field to store multiple old bits of data uniquely) (Int)
ID - Unique identifier for device (Int)
Location --Unique identifier for name of area (VarChar)
Status - The current status of the device (VarChar)
Time -- DateTime of when the last connection was made to the device (DateTime)
所以这是数据库如何看起来现在我的查询看起来像这样......
查询1
SELECT c.*,
if(HOUR(TIMEDIFF(NOW(), c.TIME)) >=1, 1, 0) as LatestOlderThanAnHour,
min(h.time) as EarliestTime,
(abs(timestampdiff(HOUR,NOW(),min(TIME)))/count(*)*100) as percentage
FROM Current c
JOIN Historical h on c.ID = h.ID
WHERE c.Location like "MyLocation"
group by c.ID
查询2
SELECT MAX(h.TIME) AS LastDown
FROM TABLENAME
WHERE h.STATUS IN ('On-Login-Screen','IE-Window-Missing')
的最终目标是添加一个 “最后向下” 列由该查询返回的每一ID。我只是无法弄清楚如何去做。
'MAX(情况下h.status在( '在登录屏幕', 'IE-窗口 - 缺少'),然后小时。时间结束)' – 2013-05-07 20:20:59
^^将其作为答案,以便我可以接受它,并非常感谢你! – 2013-05-07 20:34:07